No. Potassium chloride will not protect you from the poisonous effects of potassium cyanide, in any way.
Potassium chloride is melted at 770 oC.
Mg is magnesium. The CN- anion is named cyanide. Thus, Mg(CN)2 is called magnesium cyanide.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
No - there would be a reaction though if Chlorine and Potassium Iodide were mixed
Yes, a saturated solution of water and potassium chloride means that the solution contains the maximum amount of potassium chloride that can dissolve in water at a given temperature. Additional potassium chloride added to the solution would not dissolve and would remain as solid at the bottom of the container.
The reaction is: AgNO3 + KCl = AgCl + KNO3The precipitate is silver chloride.
When potassium cyanide (KCN) is added to water, it dissociates into potassium ions (K+) and cyanide ions (CN-). These ions can then react with water molecules to form stable complexes, such as potassium cyanide ion or hydrocyanic acid, depending on the concentration and pH of the solution. This reaction releases cyanide ions, which can be highly toxic.
To make potassium chloride and water from potassium hydroxide, you would add hydrochloric acid (HCl). The reaction would be: KOH + HCl → KCl + H2O
The molar mass of potassium chloride is 74,5513.
Astatine could potentially replace the chlorine in potassium chloride to form astatine chloride and potassium. The reaction would likely be very rare and unstable due to astatine's radioactivity and scarcity.
If you use potassium hydroxide instead of sodium hydroxide, you would make potassium salts instead of sodium salts. For example, if you reacted potassium hydroxide with hydrochloric acid, you would produce potassium chloride.
To answer this you need a roman numeral on gold to know the charge on it. Assuming it would be (I)... the formula would be KAu(CN)2