// to find the length of the string by using array
#include<stdio.h>
#include<string.h>
int main()
{
int i=0,len[21],n;
char str[8][11];
printf("no of name to be enter");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("enter the %d string : ",i);
scanf("%s",str[i]);
}
for(i=0;i<n;i++)
{
len[i]=strlen(str[i])-1;
}
for(i=0;i<n;i++)
{
printf("\n lenght of %d string are ",i);
printf("%d",len[i]);
}
return(0);
}
int strLen(char* str) {
// point current at the beginning of str
char *current = str;
// loop until we get to the null character
while( current[0] != '\0' ) {
++current;
}
return (current - str);
}
#include<stdio.h>
main()
{
char str1[100];
gets(str1);
int i=0;
i=len(str1,i);
printf(" \nlength of string is %d",i);
}
int len(char s1[],int i)
{
printf("\n%c",s1[i]);
int sum=0,count =1;
if(s1[i] == '\0')
return 0;
else
return (count += len(s1,++i));
return count;
}
int Strlen (const char* str) { int len = 0;
if (!str) return len;
while (*str++) ++len; // count all characters up to but not including the null-terminator
return len;
}
Note that this function is unsafe; if the string is not null-terminated, the function will attempt to count characters beyond the range of the string until a null character is encountered, yielding a length that may be larger than the buffer's actual capacity. However, any attempt to dereference memory that does not belong to our program will result in undefined behaviour.
To make the function safe, we must pass the maximum length of the buffer. We are then looking for a null-terminator within the range of the buffer's length. If the return value is equal to the buffer's length, then the string has no null-terminator.
int Strnlen (const char* str, int max_length) {
int len=0;
if (!str) return len; while (len<n && *str++) ++len; // count all characters up to but not including the null-terminator
return len;
}
int strlen (const char *psz) {
int i = 0;
while (*psz++ != '\0') i++;
return i;
}
what is string
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
i dont no string for servlate
Here is the algorithm of the algorithm to write an algorithm to access a pointer in a variable. Algorithmically.name_of_the_structure dot name_of_the _field,eg:mystruct.pointerfield
Nothing.The C language only recognizes a few keywords, like "for" and "if". Most of what's in a C program ... that doesn't reference routines in the C program itself ... are library calls, and cputs() is one of those. What it does is write its argument (which should be a pointer to a character string) to the console... console put string.
This is an assignment not a question.
what is string
You can write 2X, where X is the length of the string.
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
#include<stdio.h> #include<conio.h> void main() { char string[20]; int i=0; printf("Enter the string.\n"); while(i<=19) { scanf("%c",&string[i]); i++; } while(i>=0) { printf("%c",string[i]); i--; } getch(); } In this program it is compulsory to enter 20 characters. Now we can write a program in which it is not necessary. #include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[20]; int length; printf("enter the string.\n"); gets(string); length=strlen(string); length--; while(length>0) { printf("%c",string[length]); length--; } getch(); }
int mystrlen (const char *s) { const char *t; if (!s) return 0; for (t=s-1;*++t;); return t-s; }
We use a pointer to reference a string because a string is an array of characters where every element is a char (or a wchar_t if using UNICODE strings). Passing arrays by value would require the entire array to be copied, but passing a pointer variable to an array only copies the pointer, which is effectively the same as passing the array by reference. #include <iostream> int main() { char * psz = "hello"; // pointer to a null-terminated string. std::cout << psz; // pass the pointer (by value) to the insertion operator. return( 0 ); }
i dont no string for servlate
Here is the algorithm of the algorithm to write an algorithm to access a pointer in a variable. Algorithmically.name_of_the_structure dot name_of_the _field,eg:mystruct.pointerfield
Nothing.The C language only recognizes a few keywords, like "for" and "if". Most of what's in a C program ... that doesn't reference routines in the C program itself ... are library calls, and cputs() is one of those. What it does is write its argument (which should be a pointer to a character string) to the console... console put string.
i am sam
what is if(!(str[i]==32))