Write a C program to display odd numbers from 1 to n where n is accepted from user?

Answer 1

#include<stdio.h>

main()

{

int i=0,j=0,n;

printf("Enter a number:");

scanf("%d",&n);

printf("The first %d odd numbers are:-\n");

for(i=0;i<=n;i++)

{

if(j%2!=0)

printf("%d\n"j);

j=j+1;

}

}

Answer 2

You can't display ALL odd numbers because your program will be running forever, counting towards infinity. A much more useful program would be to display all odd numbers between some numbers x and y:

void displayOdds(int x, int y)

{

// Ensure that x is an odd number

if(x % 2 == 0)

x++;

for(; x <=y; x+=2)

printf("%d\n", x);

}

Answer 3

int n, i;

printf ("Enter n: ");

scanf ("%d", &n);

for (i=1, i<=n, i+=2) printf ("%d\n", i);