Write a c plus plus program to find the greatest of the three numbers?

Answer 1

This snippet assumes you have two values, x and y and you want to find the greater.

int max (int x, int y)
{
if (x > y)
{
return x;
}

return y;
}

Answer 2

if (x > y) System.out.println("The larger number is " + x);
else System.out.println("The larger number is " + y);

Or shorter, with the ternary operator:

System.out.println("The larger number is " + x > y ? x : y);

Yet another option is to use the max() method in the Match() class.

Answer 3

double firstNumber = 0;

double secondNumber = 0;

...

cout << "Enter a first number: ";

cin >> firstNumber;

...

cout << "Enter a second number: ";

cin >> secondNumber;

...

if (firstNumber > secondNumber)

{

cout << "The first number is greater!";

}

else

{

bool result = true;

...

if (firstNumber < secondNumber)

{

result = false;

}

else

{

result = true;

}

...

switch (result)

{

case true:

cout << "The numbers are equal!";

break;

case false:

cout << "The second number is greater!";

break;

}

}

Answer 4

The following demonstrates how to compare three values, returning the greatest.

The function, GreatestOf3(), is declared as a template function. This means you can call the function with any type of data, so long as all three parameters are of the same data type (int, char, float, etc). The compiler will automatically generate explicit versions of the function to cater for all the types you pass, which saves you having to write the same code over and over to cater for all possible types you might pass now or in the future. It will also cater for class instances, structs and enums, provided you implement the greater-than operator (>) for each specific type.

Note that all parameters are passed as const references. The function does not alter the parameters, hence they are declared const. They are passed by reference to avoid the creation of automatic variables (as would occur if they were passed by value, which would copy all three values locally). The return value is also a reference, but is declared non-const. In other words, it will return the largest parameter, rather than a copy of the largest parameter. The return value can be cast to a const reference by the caller, if required.

#include <iostream>

template<class T>

T& GreatestOf3(const T& t1, const T& t2, const T& t3)

{

return((T&)(t3>t2&&t3>t1?t3:t2>t1?t2:t1));

// The above line is C++ shorthand.

// Using longhand it would essentially equate to:

// if(t3>t2 && t3>t1 ) return(t3);

// else if(t2>t1) return(t2);

// Note: a final else is optional here, but is not required as all possibilities have been covered by the previous lines.

// return(t1);

};

int main()

{

// Example usage using ints and doubles:

int x=5, y=10, z=3;

std::cout<<"The greatest of {"<<x<<", "<<y<<" and "<<z<<"} is "<<GreatestOf3(x, y, z)<<std::endl;

double a=1.1, b=1.0, c=1.2;

std::cout<<"The greatest of {"<<a<<", "<<b<<" and "<<c<<"} is "<<GreatestOf3(a, b, c)<<std::endl;

return(0);

}

Output:

The greatest of {5, 10 and 3} is 10

The greatest of {1.1, 1 and 1.2} is 1.2

Answer 5

if (x > y) System.out.println("The larger number is " + x);
else System.out.println("The larger number is " + y);

Or shorter, with the ternary operator:

System.out.println("The larger number is " + x > y ? x : y);

Yet another option is to use the max() method in the Match() class.

if (x > y) System.out.println("The larger number is " + x);
else System.out.println("The larger number is " + y);

Or shorter, with the ternary operator:

System.out.println("The larger number is " + x > y ? x : y);

Yet another option is to use the max() method in the Match() class.

if (x > y) System.out.println("The larger number is " + x);
else System.out.println("The larger number is " + y);

Or shorter, with the ternary operator:

System.out.println("The larger number is " + x > y ? x : y);

Yet another option is to use the max() method in the Match() class.

if (x > y) System.out.println("The larger number is " + x);
else System.out.println("The larger number is " + y);

Or shorter, with the ternary operator:

System.out.println("The larger number is " + x > y ? x : y);

Yet another option is to use the max() method in the Match() class.