Write a c program to find the binary addition of two 8 bit numbers?

Answer 1

#include <stdio.h>

#include <iomanip>

int main()

{

int binary1[8] = {0,1,1,1,1,0,1,1}; //8 element array

int binary2[8] = {1,0,1,0,1,1,1,1}; //8 element array

int binarySum[9];

int overflow [9];

int i;

for (i=0; i<9; i++) overflow[i] = 0;

for (i=9; i >= 0; i--)

{

binarySum[i] = binary1[i] + binary2[i] + overflow[i];

if ( binarySum[i] > 1)

{

overflow[i-1] = 1;

binarySum[i] %= 2;

}

}

printf("Binary Sum is: ");

for (i = 0; i<9; i++) printf("%i", binarySum[i]);

printf("\n");

printf("\n");

printf("Carry Bit is: ");

for (i = 8 ; i>=0 ; i--) printf("%i", overflow[i]);

printf("\n");

return (0);

}

Answer 2

char x, y, z;

x= 51;

y= -78;

z= x+y;

Answer 3

char x,y,z;

x= 100;

y= 110;

z= x+y;