class Fibonacci
{
public static void main(String args[])
{
System.out.println("enter the number upto u want");
int number=Integer.parseInt(args[0]);
int a=0,b=1,c=0;
System.out.print(a+" "+b);
for(int i=1;i<=number;i++)
{
c=a+b;
System.out.print(c+" ");
a=b;
b=c;
}
}
}
the number are given to the run time where are print the series eg: 5
0 1 1 2 3 5 8 13................
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
//WAP to print fibonacci series using do-while loop.? using System; class Fibonacci { public static void Main() { int a=1,b=1; int sum=0; Console.Write("Enter Limit:"); int n=Int32.Parse(Console.ReadLine()); Console.Write(a); Console.Write(b); do { sum=a+b; a=b; b=sum; Console.Write(sum); } while(sum<n); } } By-Vivek Kumar Keshari
If you have the series stored in an array, you loop through the array and print each array element in turn. Another possibility is to print out the numbers in the series as you generate them. In that case, you may not need to store anything (depending on the series, of course).
#include<stdio.h> #include<conio.h> int fib(int a); main() { int a; clrscr(); scanf("%d",&a); for(int i=0;i<a;i++) printf("%d\n",fib(i)); } int fib(int a) { if(a==0) return 0; if(a==1) return 1; else return (fib(a-1)+fib(a-2)); }
Exactly what do you mean by 'C program in Java'
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
//WAP to print fibonacci series using do-while loop.? using System; class Fibonacci { public static void Main() { int a=1,b=1; int sum=0; Console.Write("Enter Limit:"); int n=Int32.Parse(Console.ReadLine()); Console.Write(a); Console.Write(b); do { sum=a+b; a=b; b=sum; Console.Write(sum); } while(sum<n); } } By-Vivek Kumar Keshari
write a c program to accept a number and generate a square root cube and exponential values
If you have the series stored in an array, you loop through the array and print each array element in turn. Another possibility is to print out the numbers in the series as you generate them. In that case, you may not need to store anything (depending on the series, of course).
#include<stdio.h> #include<conio.h> int fib(int a); main() { int a; clrscr(); scanf("%d",&a); for(int i=0;i<a;i++) printf("%d\n",fib(i)); } int fib(int a) { if(a==0) return 0; if(a==1) return 1; else return (fib(a-1)+fib(a-2)); }
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
write a program to print the series 1/12+1/22+.........+1/n2 ?
#include#includevoid fibonacci(int x){int f=0,m=-1,n=1,i=0;while(i
I did this as an answre to some common js questions , the question wasWrite a function which will return you first two times 1, then 2, then 3, then 5 and so on (Fibonacci numbers). Don't use any global variables.var fibonacci = (function () {var arr = [0, 1];return function () {var num = arr[arr.length - 1],len = arr.length;arr.push(arr[len - 1] + arr[len - 2]);return num;};}());//testvar i;for (i = 0; i < 10; i++) {console.log(fibonacci());}//1,1,2,3,5,8,13,21,34,55