Write a program in c language using while loop to accept n numbers and find then print largest and least number?

Answer 1

Since this is likely a homework question, what will be provided here instead of code is information that you can use to write the code. (Half of the fun of programming is the problem solving and associated trouble shooting.)

Firstly, you need to know what kind of interface the application uses: console or graphical. That'll help you determine how you'll receive the information from the user (input) and how you're displaying the results (output).

Secondly, you know that you need comparison operators and a for() loop. Since "n" is the number of values you'll accept from the user, and say "c" is the counter value, your loop will look something like: for (c=0; c<n; c++) { [your code here] }

Then you'll need four additional variables:

- one to accept the user's data;

- one to store the number from the user;

- one to store the largest value;

- one to store the smallest value.

Be sure to initialise the largest value to the smallest number you can store, and the least value to the largest number you can store. I don't know which type you're instructed to use, but for a 32-bit "int" you're looking at a range of -2,147,483,647 to 2,147,483,648.

Also, the reason you need two variables for storing the user's inputs is because the user might enter non-numeric data. So store the user's input in a char[] array, then use atoi() to convert that into an integer, and you'll be able to avoid any problems with types since atoi() ignores everything after and including the first non-digit character.

Once you've got that number, compare it with the current largest value - if the user's number is greater, set the largest value to that number. If the user's number is lower than the least number, set the least number to that value.

Once the loop is finished, simply display the results, and you're done!