What is a program to print the Fibonacci series in c plus plus?

Answer 1

Yes, you can. To generate the Fibonacci sequence, you start with the first two numbers in the sequence, usually 0 and 1. The remainder of the sequence is the sum of the previous two numbers in the sequence:

The following function will generate n terms of the sequence using first and second as the first two numbers in the sequence:

void fibonacci (int n, int first=0, int second=1) {

for (int term=0; term

int sum = first + second;

printf ("%d, ", first);

// prepare for next iteration...

first = second;

second = sum;

}

printf ("\b\b \n"); // backspace over final comma and overwrite with space

}

Answer 2

#include<iostream>

int main()

{

int x=0, y=1;

std::cout<<x<<" ";

std::cout<<y<<" ";

while( y<1000000 )

{

std::cout<<(y+=x)<<" ";

x=y-x;

}

std::cout<<std::endl;

return(0);

}

Answer 3

#include<constream.h>

void main()

{

int a,b,i=1;

cout<<"Enter a no till when u want print non fibonaci numbers\t:"

cin>>c;

cout<<"\n Non fibonaci nos \n:"

for(a=0,b=1;i<=c;i++)

{

if(i==(a=a+b))

continue;

if(i==(b=a+b))

continue;

cout<<i \t;

}

}

Answer 4

#include<iostream.h>

int main()

{

int first,sec,third;

int n;

cout<<"enter how many elements (>5).";

cin>>n;

first=0;

sec=1;

cout<<"the series is"<<first<<sec;

for(int i=2;i<=n;i++)

{

third=first+sec;

cout<<third;

first=sec;

sec=third;

}

return 0;

}