Write a program in c plus plus to a no is Armstrong or not?

Answer 1

By Dilkash

from manuu

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

long int rem,sum=0,a,len=0,num,num1,rem1;

clrscr();

printf("Enter Any Number\n");

scanf("%ld",&a);

num=a;

num1=num;

while(a!=0)

{

rem=a%10;

len=len+1;

a=a/10;

}

while(num!=0)

{

rem1=num%10;

sum=sum+(pow(rem1,len));

num=num/10;

}

if(num1==sum)

printf("\n%ld is ARMSTRONG\n",num1);

else

printf("\n%ld is Not ARMSTRONG\n",num1);

getch();

}

//MANUU POLYTECHNIC BANGALORE

Answer 2

#include <iostream>

#include <math.h> // for std::pow()

unsigned int get_length(unsigned int num,const unsigned int base=10)

{

unsigned int len=1;

while(num && (num/=base))

++len;

return( len );

}

bool is_armstrong(const unsigned int num,const unsigned int base=10)

{

unsigned int len=get_length(num,base);

unsigned int sum=0;

unsigned int tmp=num;

while(tmp)

{

sum+=(unsigned int)std::pow((double)(tmp%base),(double)len);

tmp/=base;

}

return(num==sum);

}

int main()

{

std::cout << "Armstrong series (base 10):";

for(unsigned int num=0; num<=0xffffffff; ++num)

if(is_armstrong(num))

std::cout << " " << num;

std::cout << std::endl;

return(0);

}