#include<iostream>
#include<string>
#include<sstream>
unsigned input_num (std::string prompt)
{
unsigned id = 0;
while (1)
{
std::cout<<prompt<<": ";
std::string input="";
getline (std::cin, input);
std::stringstream ss (input);
if (ss>>id)
break;
std::cout<<"Invalid input.\n";
}
return (id);
}
char input_op (std::string ops)
{
char op = 0;
while (1)
{
std::cout<<"Enter an operator ("<<ops<<"): ";
std::string input="";
getline (std::cin, input);
std::stringstream ss (input);
if (ss>>op && ops.find (op) != std::string::npos)
break;
std::cout<<"Invalid input.\n";
}
return (op);
}
int main()
{
unsigned num1 = input_num ("Enter a number");
unsigned num2 = input_num ("Enter another number");
// division is invalid if num2 is zero
char op = input_op (num2?"+-*/":"+-*");
unsigned result = 0;
switch (op)
{
case ('+'): result = num1+num2; break;
case ('-'): result = num1-num2; break;
case ('*'): result = num1*num2; break;
case ('/'): result = num1/num2;
}
std::cout<<num1<<op<<num2<<'='<<result<<std::endl;
}
Because the built in operator has the precision and compiler knows all the precision between the operators, and it works on that precision. User can also create its own operator but the compiler does not come to know thow to make precision of this operator. Therefore we dont use user defined operator
Not possible. Let's not forget than in C the followings are all operators:+, -+=, -=++, --=&, *, []function-call
int main() { int a=10,b=20; while(a--) b++; printf("%d",b); } or: a -= -b;
Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
y=2x2+3x+1
Because the built in operator has the precision and compiler knows all the precision between the operators, and it works on that precision. User can also create its own operator but the compiler does not come to know thow to make precision of this operator. Therefore we dont use user defined operator
Technically, they don't. Operators only compare values and/or assign new ones. In the case of operator overloading for class objects, the specifics of how a particular operator interacts with class data is defined within the class method.
printf ("%g\n", (n+1.0)/2);
max = a > b ? a : b; max = max > c ? max : c;
c is programming laungage
int max (int a, int b) { return a>b?a:b; }
Not possible. Let's not forget than in C the followings are all operators:+, -+=, -=++, --=&, *, []function-call
cn = c0 *( 1 + i ) pow n
int main() { int a=10,b=20; while(a--) b++; printf("%d",b); } or: a -= -b;
write a c program to fine largest/smallest of 3no (using ?:ternary operator/conditional operator)
Program is a noun that is properly defined as a public notice, a plan or system, or a written explanation to be followed. Examples of programs are: a program of regular doctor appointments or, "The program will show the time of the intermission".
Operator precedence in embedded C is exactly the same as in standard C.