Write a c program to find vowels in a character array?

Answer 1

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

main (int argc,char **argv)

{

char *a,*b,c;

int t,e;

if (argc<2) return(0);

a=argv[1];

b=a;

e=strlen(b);

for (t=0;t<=e;t++)

{

c = *b;

if (c>='A'&&c<='Z') c -= 'A'-'a';

if (c=='a'c=='e'c=='i'c=='o'c=='u') b++;

else *a++ = *b++;

}

printf ("%s\n",argv[1]);

return(0);

}

Answer 2

// Replace all vowels in str with 'z'

void replaceWithZ(char* str) {

int i = 0;

while(str[i] != 'z') {

if(isVowel(str[i])) {

str[i] = 'z';

}

++i;

}

}

// Returns 1 if ch is a vowel, 0 otherwise

int isVowel(const char ch) {

switch(ch) {

case 'a':case 'A':

case 'e':case 'E':

case 'i':case 'I':

case 'o':case 'O':

case 'u':case 'U':

return 1;

}

return 0;

}

// Sample call

int main() {

char str[] = "HELLO";

printf("%s\n", str);

replaceWithZ(str);

printf("%s\n", str);

return 0;

}

Answer 3

Basically you could have a method like this:

//returns the indexes of the vowels in char array s, optionally including Y's

int[] FindVowels(char[] s, boolean FindYs)

{

//store the number of vowels found

int VowelCount = 0;

char[] Vowels;

int[] vowelIndexes = new int[s.length];

if(FindYs) vowels = {'a','e','i','o','u','y'};

else vowels = {'a','e','i','o','u'};

for(int si = 0; si < s.length; si++)

{

for(int vi = 0; vi < vowels.length; vi++)

{

if(vowels[vi]== s[si])

{

vowelIndexes[VowelCount] = si;

VowelCount++;

}

}

}

int[] returnarray = new int[Vowelcount];

for(int i = 0; i < VowelCount; i++)

returnarray[i]=vowelindexes[i];

return returnarray;

}

Is this a C-program?

#include<stdio.h>

#include<conio.h>

int main()

{

char ar[20];

int vowc=0,i;

printf("Enter the array\n");

gets(ar);

for(i=0;i<20;i++)

{

switch(ar[i])

{

case 'a' :

case 'A' :

case 'e' :

case 'E' :

case 'i' :

case 'I' :

case 'o' :

case 'O' :

case 'u' :

case 'U' :

vowc++;

break;

default : break;

}

}

printf("%d",vowc);

return 0;

}

Answer 4

#include <stdio.h>

RemoveVowels (char *str) {

char *new = str;

while (*str != '\0') {

if (tolower(*str) != 'a' && tolower(*str) != 'e' && tolower(*str) != 'i' && tolower(*str) != 'o' &&

tolower(*str) != 'u') *(new++) = *str;

str++;

}

*(new) = '\0';

}

int main (int argc, char**argv) {

if (argc > 1) {

RemoveVowels (argv[1]);

printf ("%s\n", argv[1]);

return 0;

}

return 1;

}