int findMax(int *array)
{
int max = array[0];
for(int i = 1; i < array.length(); i++)
{
if(array[i] > max)
max = array[i]
}
return max;
}
If you are using an array : sort using qsort() then take middle element.
maxValue = function (array) {mxm = array[0];for (i=0; i<array.length; i++) {if (array[i]>mxm) {mxm = array[i];}}return mxm;}; i don't know
Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
/* using ellipses (...) to indicate tabs for clarity */ double largest (double *array, int M, int N) { ... int i, j; ... double *element; ... double answer = array[0][0]; ... for (i=0; i<M; i++) { ... ... for (j=0; j<N; j++) { ... ... ... element = array + i*M + j; ... ... ... if (*element > answer) answer = *element; ... ... } ... } ... return answer; }
If you are using an array : sort using qsort() then take middle element.
maxValue = function (array) {mxm = array[0];for (i=0; i<array.length; i++) {if (array[i]>mxm) {mxm = array[i];}}return mxm;}; i don't know
Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
/* using ellipses (...) to indicate tabs for clarity */ double largest (double *array, int M, int N) { ... int i, j; ... double *element; ... double answer = array[0][0]; ... for (i=0; i<M; i++) { ... ... for (j=0; j<N; j++) { ... ... ... element = array + i*M + j; ... ... ... if (*element > answer) answer = *element; ... ... } ... } ... return answer; }
== Java does not allow reference to memory locations. == In C: for (i=0; i<n; ++i) printf ("a[%d] is at %p\n", i, &a[i]);
The results of that programming error is undefined. You must NEVER EVER write, or EVEN READ an array element beyond the allocated size of the array. Period.I would flunk a student that consistently did this, and I would fire a programmer that did the same.
If you have the series stored in an array, you loop through the array and print each array element in turn. Another possibility is to print out the numbers in the series as you generate them. In that case, you may not need to store anything (depending on the series, of course).
// Assuming you dynamically allocated this array using "new"... delete array[arraysize - 1]; arraysize--;
int max(int arr[], int arrSize){int maximum = arr[0];for (int i = 0; i < arrSize; i++){if (maximum < arr[i]){maximum = arr;}}return maximum;}
Reference:cprogramming-bd.com/c_page1.aspx# array programming
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