#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#define MAX 50
#define N 2000
void sort_words(char *x[], int y);
void swap(char **, char **);
int main(void)
{
char word[MAX];
char *x[N];
int n = 0;
int i = 0;
for(i = 0; scanf("%s", word) == 1; ++i)
{
if(i >= N)
printf("Limit reached: %d\n", N), exit(1);
x[i] = calloc(strlen(word)+1, sizeof(char));
strcpy(x[i], word);
}
n = i;
sort_words(x, n);
for(i = 0; i < n; ++i)
printf("%s\n", x[i]);
return(0);
}
void sort_words(char *x[], int y)
{
int i = 0;
int j = 0;
for(i = 0; i < y; ++i)
for(j = i + 1; j < y; ++j)
if(strcmp(x[i], x[j]) > 0)
swap(&x[i], &x[j]);
}
void swap(char **p, char **q)
{
char *tmp;
tmp = *p;
*p = *q;
*q = tmp;
}
void main()
{
int i,j,temp1,temp2;
int arr[8]={5,3,0,2,12,1,33,2};
int *ptr;
for(i=0;i<7;i++)
{ for(j=0;j<7-i;j++) {
if(*(arr+j)>*(arr+j+1))
{ ptr=arr+j;
temp1=*ptr++;
temp2=*ptr;
*ptr--=temp1;
*ptr=temp2;
clrscr();
for(i=0;i<8;i++)
printf(" %d",arr[i]);
getch(); }
#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>
void sortname(char *name[],int size);
void main()
{
int c=0 ,i;
char *name1[10];
name1[c]=(char*)malloc(10*sizeof(char));
printf("enter the name:::::( ( press end to terminate ) )");
scanf("%s",name1+c);
if(strcmp(name1[c],"end")!=0)
{
c++;
name1[c]=(char*)malloc(10*sizeof(char));
printf("enter the name:::::( ( press end to terminate ) )");
scanf("%s",name1+c);
}
else
{
sortname(name1,c-1);
}
printf("the sorted names are:");
for(i=0;i<c-1;i++)
{
printf("%s",*name1+i);
}
getch();
}
void sortname(char *name[], int size)
{
int j,k;
char temp[10];
for(j=0;j<size-1;j++)
{
for(k=j+1;k<size;j++)
{
if(strcmp(name[j],name[k])>0)
{
strcpy(temp,name[j]);
strcpy (name[j],name[k]);
strcpy(name[k] ,temp);
}
}
}
}
This is not a question, but directions. You need to do this.
An array of pointers is exactly what it sounds like - one or more pointers arranged in order in memory, accessible through a common base name and indexed as needed. Philosophically, there is no difference between an array of pointers and an array of objects...int a[10]; // 10 integers, named a[0], a[1], a[2], ..., a[9]int *b[10]; // 10 pointers to int, named b[0], b[1], b[2], ..., b[9]If you initialize the array of pointers...int i;for (i = 0; i < 10; i++) b[i] = &a[i];... then *b[0] would be the same as a[0], etc.
An array of pointers is a contiguous block of memory that contains pointers to other memory locations. They essentially allow non-contiguous memory locations to be treated as if they were an actual array.
Reference:cprogramming-bd.com/c_page1.aspx# array programming
To write a C++ program to display the student details using class and array of object.
How to write a program for mouse in microprocessor?
sorry
An array of pointers is exactly what it sounds like - one or more pointers arranged in order in memory, accessible through a common base name and indexed as needed. Philosophically, there is no difference between an array of pointers and an array of objects...int a[10]; // 10 integers, named a[0], a[1], a[2], ..., a[9]int *b[10]; // 10 pointers to int, named b[0], b[1], b[2], ..., b[9]If you initialize the array of pointers...int i;for (i = 0; i < 10; i++) b[i] = &a[i];... then *b[0] would be the same as a[0], etc.
I guess it is an 'array of pointers'. Example:int main (int argc, char *argv[])
assembly language program for sorting an array using 8086 microprocessor.
Create an array with 50 elements and input the integers one a time, filling the array. Use an insertion sort on the array for each input except the first. Alternatively, input the values first and then use insertion sort.
An array of pointers is a contiguous block of memory that contains pointers to other memory locations. They essentially allow non-contiguous memory locations to be treated as if they were an actual array.
Reference:cprogramming-bd.com/c_page1.aspx# array programming
How to write a program for mouse in microprocessor?
To write a C++ program to display the student details using class and array of object.
Add the numbers into one variable as you read them in. But if you prefer, you can read the numbers into an array and then use a loop to add the numbers together.
A Jagged array is an array of arrays. You can initialize a jagged array as − int[][] scores = new int[2][]{new int[]{92,93,94},new int[]{85,66,87,88}}; Where, scores is an array of two arrays of integers - scores[0] is an array of 3 integers and scores[1] is an array of 4 integers.
You would use an array of pointers to pointers whenever you wished to implement a dynamic multi-dimensional array of 3 or more dimensions. Every multi-dimensional array can ultimately be reduced to a one-dimensional array where each element is itself a one-dimensional array (an array of arrays). With fixed-size arrays, all elements can be allocated contiguously regardless of how many dimensions there are. Fixed size arrays can be allocated both statically (when the size is known at compile time) or dynamically (when the size is unknown at compile time). However with large arrays it is often necessary to divide the array into smaller subarrays each of which is allocated separately (non-contiguously with each other) and maintain a separate array of pointers to keep track of each of those subarrays. Although this consumes more memory than a contiguously-allocated array would, it has the added benefit in that each subarray need not be the same length, thus it can actually save memory overall. However, if we had several such arrays then we would need yet another array in order to keep track of them all, and this array would need to be an array of pointers to pointers.