Write the program that display the factorial of a number?

Answer 1

/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */

#include <stdio.h>

int main ( )

{

int n , factorial = 1 ;

printf ( "enter the value of n\n") ;

scanf ( "%i" , & n ) ;

while ( n != 0 )

{

factorial *= n ;

n -- ;

}

printf ( "The factorial of n is\n%i\n" , factorial ) ;

return 0;

}

Answer 2

unsigned long factorial(unsigned long n) {

if (n = 2) return n else return n * factorial(n - 1);

} This is a recursive approach. Note very carefully that it will fail when the range of an unsigned long is exceeded. In a 32-bit environment, the maximum value of an unsigned long is 4,294,967,296, and the maximum value of n in this case is 12. The factorical of 12 is 479,001,600, which fits, but the factorial of 13 is 6,227,020,800, which does not fit. You could go unsigned long long (a 64-number), if you platform supports it, which would give you a maximum factorial of 20, which is 2,432,902,008,176,640,000. Anything larger, and you need an arbitrary precision decimal multiplier. You could implement this with linked lists.

Answer 3

#include <iostream>

#include <cctype>

using std::cin;

using std::cout;

using std::endl;

using std::tolower;

long factorial(const int& N);

int main()

{

int N = 0; //factorial of N

char command = 'n';

do

{

cout << "Enter a number to calculate factorial: ";

cin >> N;

cout << endl << "Factorial of " << N << " is: " << factorial(N) << endl;

cout << "Do you want to continue (y/n)?";

cin >> command;

cout << endl;

} while ('y' 0)

{

return 1;

}

else

{

return (N * factorial(N - 1));

}

}

Answer 4

int main() { // Variable declarations. unsigned long int factorial = 1 , number = 1; // reads a number for finding its factorial. cout << "Input a non-negative number: "; cin >> number; while( number > 1 ) { factorial *= number * ( number - 1 ); number -= 2; } cout << "Factorial is: " << factorial << endl; system("PAUSE"); return 0;

Answer 5

#include <iostream>

using namespace std;

int fact(int x);

int main()

{

int x, total;

cout << "Enter a number: ";

cin >> x;

total = fact(x);

cout << "The factorial of " << x << " is: " << total << endl;

char wait;

cin >> wait;

return 0;

}

int fact(int x)

{

if(x == 1)

{

return 1;

}

return fact(x - 1) * x;

}

Answer 6

void main()

{

int i,b=1,n;

printf("enter the number:");

scanf("%d",&n);

for(i=n;i<=n;i--)

b=b*i;

printf("factorial number is:%d",b);

getch();

}

Answer 7

/*this is the program to find the factorial to n numbers*/

#include<stdio.h>

void main()

{

int n,f,factorial(int);

printf("which number facrorial you want?");

scanf("%d",&n);

f=factorial(n);

printf("The factorial upto %d is %d",n,f);

}

int factorial(int a)

{

if(a==0)

return 1;

else

return (a)*factorial(a-1);

}