#include
#include
void
main()
int prime(int n)
{
int i, j=n/2;
clrscr();
for(i=2; i<=j; i++)
{
if(n%j==0)
return 0;
}
return 1;
}
void
main()
{
int a,b,i;
clrscr();
printf("\n enter the twin prime numbers");
scanf("d",&a,&b);
printf("\n twin prime within this range \n");
if(a%2!==0)
i=a+1;
else;
i=a;
while(i+2<=b)
{
if(prime (i) &&prime(i+2) )
printf("\n%d\t%d",i,i+2);
i+1=2;
}
getch();
}
#include
#include
void main()
{
Int i, j, C;
printf("Enter the no");
Scanf("%d", &n);
for(j=2; j { If(n%j==0) { c++; } } if(c==0) { printf(" Entered no is prime no"); } getch(); } #include #include #include void main() { int i,j; clrscr(); for(i=3;i<=1000;i++) { for(j=2;j<=i;j++) { if(i%j==0) break; } if(i==j) cout< } getch(); // this is the easiest method for finding prime nos made by Taabi } B: To write the c version: i.e not C++, you write: A: /****************************** * THIS IS THE EASIEST * METHOD OF GENERATING * PRIME NUMBERS USING C * MADE BY: githambo@gmail.com *******************************/ #include
#include<iostream>
#include<cmath>
unsigned is_prime (const unsigned num) {
if (num<2) return false; // 0 and 1 are not prime
if ((num%2)==0) return num==2; // 2 is the only even prime
unsigned max_factor {(unsigned) sqrt ((double) num) + 1}; // test all odd factors >=3
for (unsigned factor {3}; factor<max; ++factor)
if ((num%factor)==0) return false;
return true; // the number is prime!
}
unsigned next_prime (unsigned num) {
while (!is_prime(++num));
return num;
}
int main() {
std::cout<<"2-digit Twin Primes\n\n";
unsigned a {2}, b {3};
while (b<100) {
if ((b-a)==2) std::cout<<"Prime twins: "<< a << " & " << b << '\n';
a=b;
b=next_prime (++b);
}
std::cout<<std::endl;
}
look man that would take alot >>> Ill give you the way =============================================================================== this answer i write it now on net ! i read about that befor in it uni where i study i will chick out the answer and re write it best wishes 2024
PRINT 2,3,5,7,11,13,17,19,23,29,31,37
Here is a simple program to generate prime numbers upto a given specific number /*Prime No. from 1 to 50*/ /*By-Himanshu Rathee*/ #include<stdio.h> #include<conio.h> void main() { int i,j,n; clrscr(); printf(" Enter the number upto which we have to find the prime number: "); scanf("%d",&n); printf("\n"); for(i=2;i<=n;i++) { for(j=2;j<=i-1;j++) if(i%j==0) break; /*Number is divisble by some other number. So break out*/ if(i==j) printf("\t%d",i); /*Number was divisible by itself (that is, i was same as j)*/ } /*Continue loop upto nth number*/ getch(); }
(defun prime (num) (if (< 2 num) (do ((dividend 2 (1 + dividend)) (chk-to (sqrt num))) ((equal (rem num dividend) 0)) (when (<= chk-to dividend) (return t))) t))
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
Its impossible, there are only 5 single digit numbers that are not prime
VBnet program to find the prime numbers between 100 to 200?
There are 21 two-digit prime numbers.
fdsgfhgdfhgdf
Prime numbers are numbers that are only divisible by themselves and the number 1. You can write a program to print all prime numbers from 1 to 100 in FoxPro.
Since there is an infinite set of prime numbers the answer would be infinity.
This is a homework question and does not deserve an answer because you will learn nothing other than being lazy.
There are 17 such numbers.
2, 3, 5, and 7 are the only one-digit prime numbers.
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
17, 37, 47, 67, 97
997 is the largest 3-digit prime number.