Write a program to subtract two 3x3 matrices?

Answer 1

The value of a static global variable can never be changed whereas the value of a simple global variable can be changed.

how to create a 3x3 matrix written in c++:

#include

#include//this is only for if you want a string matrix

using namespace.std;

int main()

{

string yourstinghere[3][3];

}

Answer 2

Depends on the language and how you're wanting to add them, but generally it will look something like this.

for(int i =0;i < Example.length;i++)

{

for(int j = 0;j < Example.length;j++)

{

newValue = newValue + Example[i][j];

}

}

Answer 3

/* Write a C program that uses functions to perform the following:

i) Addition of Two Matrices

ii) Multiplication of Two Matrices

*/

#include<stdio.h>

void main()

{

int ch,i,j,m,n,p,q,k,r1,c1,a[10][10],b[10][10],c[10][10];

clrscr();

printf("************************************");

printf("\n\t\tMENU");

printf("\n**********************************");

printf("\n[1]ADDITION OF TWO MATRICES");

printf("\n[2]MULTIPLICATION OF TWO MATRICES");

printf("\n[0]EXIT");

printf("\n**********************************");

printf("\n\tEnter your choice:\n");

scanf("%d",&ch);

if(ch<=2 & ch>0)

{

printf("Valid Choice\n");

}

switch(ch)

{

case 1:

printf("Input rows and columns of A & B Matrix:");

scanf("%d%d",&r1,&c1);

printf("Enter elements of matrix A:\n");

for(i=0;i<r1;i++)

{

for(j=0;j<c1;j++)

scanf("%d",&a[i][j]);

}

printf("Enter elements of matrix B:\n");

for(i=0;i<r1;i++)

{

for(j=0;j<c1;j++)

scanf("%d",&b[i][j]);

}

printf("\n =====Matrix Addition=====\n");

for(i=0;i<r1;i++)

{

for(j=0;j<c1;j++)

printf("%5d",a[i][j]+b[i][j]);

printf("\n");

}

break;

case 2:

printf("Input rows and columns of A matrix:");

scanf("%d%d",&m,&n);

printf("Input rows and columns of B matrix:");

scanf("%d%d",&p,&q);

if(n==p)

{

printf("matrices can be multiplied\n");

printf("resultant matrix is %d*%d\n",m,q);

printf("Input A matrix\n");

read_matrix(a,m,n);

printf("Input B matrix\n");

/*Function call to read the matrix*/

read_matrix(b,p,q);

/*Function for Multiplication of two matrices*/

printf("\n =====Matrix Multiplication=====\n");

for(i=0;i<m;++i)

for(j=0;j<q;++j)

{

c[i][j]=0;

for(k=0;k<n;++k)

c[i][j]=c[i][j]+a[i][k]*b[k][j];

}

printf("Resultant of two matrices:\n");

write_matrix(c,m,q);

}

/*end if*/

else

{

printf("Matrices cannot be multiplied.");

}

/*end else*/

break;

case 0:

printf("\n Choice Terminated");

exit();

break;

default:

printf("\n Invalid Choice");

}

getch();

}

/*Function read matrix*/

int read_matrix(int a[10][10],int m,int n)

{

int i,j;

for(i=0;i<m;i++)

for(j=0;j<n;j++)

scanf("%d",&a[i][j]);

return 0;

}

/*Function to write the matrix*/

int write_matrix(int a[10][10],int m,int n)

{

int i,j;

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%5d",a[i][j]);

printf("\n");

}

return 0;

}

Answer 4

#include<stdio.h>

void main()

{

int a[3][3],b[3][3],c[3][3],i,j;

printf("Enter the First 3x3 Matrix : ");

for(i=0;i<3;i++)

{

for(j=0;j<3;j++)

scanf("%d",&a[i][j]);

}

printf("Enter the Second 3x3 Matrix : ");

for(i=0;i<3;i++)

{

for(j=0;j<3;j++)

scanf("%d",&b[i][j]);

}

printf("\nThe Sum of Matrices is : ");

for(i=0;i<3;i++)

{

for(j=0;j<3;j++)

{

c[i][j]=a[i][j]+b[i][j];

printf("%d ",&c[i][j];

}

printf("\n");

}

printf("\n\nThe Difference of Matrices is : ");

for(i=0;i<3;i++)

{

for(j=0;j<3;j++)

{

c[i][j]=a[i][j]-b[i][j];

printf("%d ",&c[i][j];

}

printf("\n");

}

}

Answer 5

Presumably, both the original matrices and the result matrix would be stored in 2-dimensional arrays; to do the actual addition, write two "for" loops, one for each row, and one for each column. Inside the inner "for" loop, just add the corresponding elements and place the result in the result matrix.