Such a method could be: public int NumberOfDigits(int num) { num = num/10; if( num == 0) return 1; return ( 1+NumberOfDigits(num) ); }
There is Int64 class, it will do it.
Add the last digit plus the sum of all the previous digits. The base case is that if your integer only has a single digit, just return the value of this digit. You can extract the last digit by taking the remainder of a division by 10 (number % 10), and the remaining digits by doing an integer division by 10.
num=32767 MsgBox(len(num))
52
There are different ways to do it. One is to convert it to a String, then use the string manipulations methods to extract individual digits as strings. You can then convert them back to numbers. Another is to do some calculations. For example, to get the last digit: int i = 12345; int lastdigit = i % 10; //To get additional digits, divide by 10 and repeat: i /= 10; int lastdigit = i % 10; In this case you can create a loop for this (repeating while i > 0), and copy the digits to an array.
A positive integer plus a positive integer is equal to a positive integer. For example, 2 + 2 = 4. The two digits being added together are called the addends, while the answer is called the sum.
The digits of the number without any positive or negative sign. It will look just like the positive version of the integer.
The answer is 198.
yes, any positive or negative number is an integer
It is -987. The smallest positive 3-digit integer with unique digits is 102.
81
The answer is a negative or positive integer with one or two digits.
Basically a number without decimals (digits after a decimal point). this can be either positive or negative.
The least possible integer is -98765432. The least possible positive integer is 10234567.
12
There is Int64 class, it will do it.
The smallest positive integer is 1357.