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Write an equation for the formation of NH3 g from its elements in its standard states?
Wiki User
∙ 12y ago
1/2 n2 + 3/2 h2 = nh3 sorry about the lower case they wouldn't let me summit it with caps
N2 + 3 H2 => 2 NH3
Wiki User
∙ 12y ago
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Write an equation for the formation of HF gas from its elements in its standard states?
1/2H2(g) + 1/2F2(g) -> HF(g)
What is a standard formation reaction?
A standard formation reaction is the reaction of the ions which make up a compound in their standard states. For example, the standard formation reaction of H2SO4 is: 2H+(g) + SO42-(g) --> H2SO4 (l)
What is the basic difference between enthalpy of formation?
Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1
What information you get from chemical equation?
You get the reactants, products, and the ratio that the chemicals react in. It also gives information on what processes the chemicals are undergoing, such as oxidation/reduction and acid/base.
What law states that the number of atoms on the right of a chemical equation is equal to the number of atoms on the left of the chemical equation called?
This is the law of mass conservation.
Write an equation for the formation of HF gas from its elements in its standard states?
1/2H2(g) + 1/2F2(g) -> HF(g)
What is a standard formation reaction?
A standard formation reaction is the reaction of the ions which make up a compound in their standard states. For example, the standard formation reaction of H2SO4 is: 2H+(g) + SO42-(g) --> H2SO4 (l)
What is the basic difference between enthalpy of formation?
Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1
How elements from helium to iron are created?
The accepted modern theory of elemental formation states: The lighter elements are a bi-product of nuclear fusion from stellar masses (stars).
What is the standard enthalpy of formation of hydrogen bromide?
[from wikipedia] The standard enthalpy of formation"standard heat of formation" of a compound is the change of enthalpy that accompanies the formation of 1 mole of a substance in its standard state from its constituent elements in their standard states (the most stable form of the element at 1 bar of pressure and the specified temperature, usually 298.15 K or 25 degrees Celsius). Its symbol is ΔHfO.
Do you have to include the elements atomic number when you write an element?
If you are representing a nuclide, then yes. (i.e. If you are representing a symbolic chemical equation, then no. If you are representing an ionic chemical equation, then only the oxidations states. (i.e. valencies)
What is triple the quotient of a number and seven is fifteen?
It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15
As the equation is written which element is not in balance Explain?
An equation written may or may not be balanced. It is balanced if the number of elements on both sides of the arrow, that is before and after the reaction, is equal. Sometimes the number of elements is not the same on both sides of the arrow, then we need to balance the equation. This is done in accordance to the law of conservation of mass which states that the mass of a substance does not get destroyed or created due to a chemical reaction.
An equation that states that two ratios are equal?
An equation that states that two ratios are equal is a proportion.
An equation states that two quantities are what?
An equation states that the two quantities on each side of the equal sign are equal.
Discuss the formation of states according to materialists and idealists views?
state formation according to idealist views
Sodium and chlorine atoms combine readily because they both tend to lose electrons true or false?
both, since both are one electron short of a stable octet, hence why both are reactive elements. Bond formation is favoured with other elements, though the natural states of the elements are different, group one and seven will b0nd preferentially if poossible.
