Write c plus plus program that compare 3 integer numbers and print out the smallest one among them?

Answer 1

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {

int a,b,c,d,g=0,s=0;

a=Integer.parseInt(jTextField1.getText());

b=Integer.parseInt(jTextField2.getText());

c=Integer.parseInt(jTextField3.getText());

d=Integer.parseInt(jTextField3.getText());

if(a>b){

if(b>c){g=a;s=c;}

else{g=a;s=b;}

}

else if(b>c){

if(c>a){g=b;s=a;}

else{g=b;s=c;}

}

else if(c>a){

if(b>a){g=c;s=a;}

else {g=c;s=c;}

}

switch(d){

case 1:JOptionPane.showMessageDialog(this, "the greates no. is"+g);

break;

case 2:JOptionPane.showMessageDialog(this, "the smallest no. is"+s);

break;

default:JoptionPane.showMessageDialog(this," please enter the choice"+"correctly 1 for greatest and 2 for smallest");

}

Answer 2

#include <iostream>

#include <vector>

#include <algorithm>

using namespace std;

int main()

{

vector<int> x;

int y;

cout << "Enter 3 numbers: " << endl;

for(int i = 0; i < 3; i++)

{

cin >> y;

x.push_back(y);

sort(x.begin(), x.end());

}

cout << x[0] << " was the lowest number entered!" << endl;

return 0;

}

Answer 3

#include<iosys.h>

// return smallest of two numbers

int min (int a, int b) {

return a<b?a:b;

}

// return smallest of three numbers

int min3 (int a, int b, int c) {

return min (min (a, b), c);

}

int main () {

int a, b, c;printf ("Enter 3 numbers:\n");

scanf ("%d %d %d", &a, &b,&c);

printf ("Smallest number is %d\n", min3 (a, b, c));

return 0;

}