235 235 0
Th= Pa + e
90 91 -1
It is Th > Pa + e. 90 91 -1
The equation can be written as:
Th-230(alpha)Ra-226
90 over 43 Tc->90 over 43 Tc + y
The atom of protactinium 234 is formed/
alpha particles.
229Th-------alpha particle-----------225Ra
If a uranium-244 atom undergoes alpha decay, it will become an atom of thorium-240. If we wrote an equation, it might look like this:92244U => 90240Th + 24He++The uranium-244 is transmuted into throium-240, and the alpha particle, which is a helium-4 nucleus (and represented as such) emerges at the tail end of the equation.
The decay product of uranium 238 by alpha disintegration (not beta or gamma) is thorium 234.
Alpha decay is basically a helium atom, so 235-4= 231. And 92-2=90 (Uranium's atomic number minus helium's). The element with atomic number 90 is Thorium. The mass is 231, so you should have Th-231 (Thorium-231).
Thorium-234 don't emit alpha particles.
alpha particles.
It is 90.
Uranium 238 is transformed in thorium 234 by alpha decay.
229Th-------alpha particle-----------225Ra
If a uranium-244 atom undergoes alpha decay, it will become an atom of thorium-240. If we wrote an equation, it might look like this:92244U => 90240Th + 24He++The uranium-244 is transmuted into throium-240, and the alpha particle, which is a helium-4 nucleus (and represented as such) emerges at the tail end of the equation.
The isotope thorium-232 is an alpha emitter; extremely rare are decays by spontaneous fission or double beta emission.
Th-230(alpha)Ra-226.
The reaction is:U-238(alpha)Th-234
alpha
alpha
100Fm254 .........> 98Cf250 + 2He4