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Time to reach the bottom would be got from t = ./(2 * 54 / 9.8) = 3.32 s

Here the horizontal component of the velocity would remain the same. So the horizontal range is got right from 9 * 3.32 = 29.88 m.

So we could find the key at a distance of 30 m right from the base of cliff.

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Q: You accidentally throw your car keys horizontally at 9.0 ms from a cliff 54 m high How far from the base of the cliff should you look for the keys?
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