the equation for this are?
aldehyde + acidified potassium permanganate
RCHO + 2KMnO4 + H2SO4 → RCOOH + K2SO4 + 2MnO2 ↓+ H20
aldehyde + Tollen's reagent
RCHO + 2AgNO3 + 2NH4OH → RCOOH + 2Ag↓ + 2NH4NO3 +H2O
aldehyde+ Fehling's reagent
RCHO + 2CuSO4 + 4NaOH →RCOOH + Cu2O↓+ 2Na2SO4 + 2H2O
THAT's ALL I KNOW
aldehyde + Sodium Hydrogen Sulfite
I think you are referring to the test using Fehlings solution. Fehlings solution oxidises aldehydes and ketones and formic acid and is in turn reduced. The red precipitate is the copper(I) oxide formed by reduction of the copper(II) complex found in Fehlings solution. Acetic acid is not readily oxidised and so there is no precipitate. See link for more information on what the complex is in Fehlings solution and how it is prepared.
Fehling test is used for reducing sugars.
When Fehling's solution is added to an aldehyde it turns brick red
When the two Fehling Solutions A and B are mixed, a deep blue solution containing a complex cupric ion is formed. On interaction with reducing compounds such as aldehydes or sugars, the copper is reduced to the univalent stage, and a red, yellow, or yellowish green precipitate is formed.
Fehling's solution must be freshly prepared because there is a tendency for it to oxidize if not used right away
Fehling solution "A" is copper sulphate solution and Fehling solution "B" is a solution of sodium potassium tartrate and NaOH.
The Fehling A solution contain copper sulfate.The Fehling B solution contain sodium potassium tartrate and sodium hydroxide.
ulo nyo!!
I think you are referring to the test using Fehlings solution. Fehlings solution oxidises aldehydes and ketones and formic acid and is in turn reduced. The red precipitate is the copper(I) oxide formed by reduction of the copper(II) complex found in Fehlings solution. Acetic acid is not readily oxidised and so there is no precipitate. See link for more information on what the complex is in Fehlings solution and how it is prepared.
benedicts test
Fehling test is used for reducing sugars.
wrt
When Fehling's solution is added to an aldehyde it turns brick red
yes.
When the two Fehling Solutions A and B are mixed, a deep blue solution containing a complex cupric ion is formed. On interaction with reducing compounds such as aldehydes or sugars, the copper is reduced to the univalent stage, and a red, yellow, or yellowish green precipitate is formed.
Fehling's solution must be freshly prepared because there is a tendency for it to oxidize if not used right away
After hydrolysis sucrose did give a positive test. It reduces sugar that has hemiketal and hemiaetal in it.