Try this site: http://www.Google.com/search?sourceid=navclient&ie=UTF-8&rlz=1T4GGLF_en&q=roswell%2c+NM%7epower+rates
Sorry, wrong page, this is the one: http://www.eia.doe.gov/cneaf/electricity/epm/table5_6_a.html
NIPSCO serves about 800,000 gas customers in northern indiana.
The cost of electricity in Minneapolis is about 6.5 cents per KWH.
First, divide watts by 1000 to get kilowatts: watts / 1000 = kW Then multiply kilowatts by the hours of usage to get kilowatt-hours kW * hours = kWh Finally, multiply kilowatt-hours by the cost per: kWh * (cost per kWh) = cost to operate
25 watts * 24 hours = 600 watt hours = 0.6 kwh {1 kilowatt hour = 1000 watt hours} 0.6 kwh * (0.085156 per kwh ) = 0.0510936 or about 5.1 cents
The fan has a rated load of 2 kW. It is this wattage times the amount of hours the fan is used times the cost of a kWh in your area that the cost is based on.
NIPSCO serves about 800,000 gas customers in northern indiana.
Coal cost about $o.o54 cents per kwh
Multiply the figure by your cost per kwh. The kwh cost is available from your local power company or utility. For instance, if a kwh was priced at 7.6 cents/kwh, then the total cost would be a bit over $30.
The cost of a kWh is 0.1029 or 10 and a third cents for every hour that you use.
The cost of electricity in Minneapolis is about 6.5 cents per KWH.
The energy cost depends on the size of the system. Large concentrated systems cost $0.10-$0.15 per kWh. Medium and small scale systems can cost from $0.25-$0.50 per kWh, when averaged.
$0.08 / Kwh for avg residential
$14.00 + 14.300c is the cost per kwh in North Haven Connecticut
Find the consumption of power in kwh for a given period. Find the corresponding cost. Divide cost by the total kwh. Most energy companies indicate the average kwh cost incurred for a given month in their monthly statements.
It costs [ 0.0005 x (power in watts used by the radio) x (cost of 1 KWh in your area) ]
28p
First, divide watts by 1000 to get kilowatts: watts / 1000 = kW Then multiply kilowatts by the hours of usage to get kilowatt-hours kW * hours = kWh Finally, multiply kilowatt-hours by the cost per: kWh * (cost per kWh) = cost to operate