0 in the elemental form, +3 in its compounds
The oxidation number of Al is +3.
In aluminum oxide (Al₂O₃), the oxidation number of aluminum (Al) is +3, while the oxidation number of oxygen (O) is -2. Since there are two aluminum atoms contributing a total of +6 and three oxygen atoms contributing a total of -6, the compound is electrically neutral, confirming these oxidation states. Thus, the oxidation numbers are +3 for Al and -2 for O.
Roman Numeral
Yes. It is true. An atom with a different atomic number is an atom of a different element.
0 in elemental form +3 in its compounds
The oxidation number of Al in Al2Br6 is +3. Each bromine atom has an oxidation number of -1, and since the compound is neutral, the sum of the oxidation numbers must equal zero. Hence, each Al atom must have an oxidation number of +3 to balance the -6 from the bromine atoms.
The oxidation number of aluminum (Al) in Al2S3 is +3, while the oxidation number of sulfur (S) is -2. Each aluminum atom has an oxidation number of +3, and each sulfur atom has an oxidation number of -2 in order to balance the charge in the compound.
The oxidation number of the central atom Al in AlF6^3- is +3. This is because each F atom contributes a -1 charge, and the overall charge of the complex ion is -3, so the Al atom must have a +3 oxidation state to balance it out.
The oxidation number of each carbon atom in C6H8O6 is +4. Each hydrogen atom has an oxidation number of +1, and each oxygen atom has an oxidation number of -2.
The oxidation number of Al in NaAlH4 is +3. This is because Na has an oxidation number of +1, H has an oxidation number of -1, and the overall compound has a neutral charge. Therefore, the oxidation number of Al can be calculated as +3.
The oxidation number for hydrogen in a neutral atom is 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
In AlOH^1-, oxygen typically has an oxidation number of -2. Since the overall charge of AlOH^1- is -1, the oxidation number of Al can be calculated as follows: (oxidation number of Al) + (oxidation number of O) + (oxidation number of H) = -1. Solving for Al gives an oxidation number of +3.
Oxidation is a chemial reaction; the atom and the number of neutrons remains unchanged.
The oxidation number for Al in AlF3 is +3. This is because fluoride (F) has an oxidation number of -1, and the overall compound is neutral, so the oxidation number of Al must be +3 to balance the charges.
In S2Cl2, each sulfur atom has an oxidation number of 0, and each chlorine atom has an oxidation number of -1.
The oxidation number of Al is +3.