tight as you can make it,
around 150 foot lbs.
very tight.
Two
suspend the car from the frame (UNDER THE CABIN ) HAVE THE AXLES FREE . REMOVE TORQUE CONVERTER COVER AND THERE IT COMES THE OIL PAN
GM 10 bolts with 8 lug pattern. Some fronts are the similar Dana 44
180 ft pounds is recommended for all cv axles
It could be the shift motor on the T Case. Or it could be the automatic shift button switch on the dash.
Because both axles are powered. You have what's known as a 6x4 truck.. the driveshaft comes off the transmission tail shaft, and it goes into the interaxle differential pinion. That interaxle differential provides torque to both axles at all times - not just when the interaxle differential lock (sometimes referred to as a 'power divider lock') is engaged. Locking the interaxle differential simply locks it to ensure that outputs to both axles rotate at the same speed.
Torque converter, fluid cavitation, bearings, excessive end play on axles ... you name it.
NO YOU CAN NOT. THE AXEL SHAFT IS WHAT HOLDS THE FRONT WHEEL BEARINGS TOGETHER,WHEN YOU TIGHTEN THE BIG NUT IN THE CENTER OF THE WHEEL. ARE ON THE END OF THE AXELSHAFT.
I would doubt it. The gears are usually dimensionally different in the front and rear axles. NO!
The different types of axles used in bike manufacturing are solid axles, quick release axles, and thru-axles.
We'd need to know if you were referring to the outer or inner nut (or both), and also if your truck has the proprietary Mack axles or if it has the Dana Spicer axles. For the Dana Spicer axles, I can tell you you set the inner initially to 300 - 350 ft/lbs to seat the spindle, then you back it off, tighten it to 50 ft/lbs (then tighten it as needed to get the perforated ring aligned properly with the inner spindle nut), and the outer to 250 ft/lbs. Not sure about the Mack axles.
4-wheeled cars have 4 axles. Depending on the type of drive-train that the car uses, some of the axles might only be stub axles or hubs, and some axles might be referred to as 'spindles', but they are all, 'axles', nonetheless.