0
It is not 330 ohms it is a value that must be installed in series to insure a 20ma or so of current limiting. This value of 330 ohms can change greatly if the source voltage changes greatly. It also has to be noted that the LEDS are not created equally So each LED voltage drop can be added to the equation.
What else can I help you with?
Why you use 250 Ohm resistor in series with HART protocol communication?
You need to use the 250 Ohm resistor in series with HART protocol communication because it acts as a shunt resistor.
A 120 oh resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. What is te current running through te 40 ohm resistor?
To find the current through the 40 ohm resistor, first calculate the total resistance of the parallel circuit: 1/Rt = 1/120 + 1/60 + 1/40. Then, calculate the total current using Ohm's Law, I = V/Rt. Finally, use the current divider rule to find the current passing through the 40 ohm resistor.
What resistor should you use to get 9v to 6v?
You can only use a resistor to drop a voltage at a constant current. If you know the current, use Ohm's law to calculate the resistor value.
A 120 ohm resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. What is the current running through the 60 ohm resistor?
To calculate the current running through the 60 ohm resistor in a parallel circuit, you first need to find the total resistance of the circuit. For a parallel circuit, the reciprocal of the total resistance (1/RT) is equal to the sum of the reciprocals of the individual resistances (1/R1 + 1/R2 + 1/R3). Once you find the total resistance, you can use Ohm's Law (I = V/R) to calculate the current running through the 60 ohm resistor.
Calculate the power used in 2ohm resistor in each what circuits- 1 a 6V battery in series wid 1ohm and 2ohm resistors 2 a 4V battery in parallel wid 12ohm and 2ohm resistors?
1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:Total resistance = 3 ohms.Current in the loop = 6/3 = 2 amperesPower dissipated by the 2-ohm resistor - I2R = 8 watts.2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallelThe 12-ohm resistor is irrelevant.4 volts across the 2-ohm resistor.Power dissipated by the 2-ohm resistor = E2/R = 8 watts.
A 120 resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source what is the current running though the 40 ohm resistor?
To calculate the total current in the circuit, you first need to find the total resistance by using the formula for resistors in parallel: 1/Total Resistance = 1/120 + 1/60 + 1/40. Once you have the total resistance, you can use Ohm's Law: Current = Voltage / Total Resistance. Finally, to find the current running through the 40 ohm resistor, you divide the total current by the resistance of the 40 ohm resistor.
A 120 ohm resisto a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source What is the current running through the 60 ohm resistor?
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.
What size resistor to change 12 volts to 3 volts for a led?
Assuming that you're talking about 12V DC you would use a 4 ohm resistor. If you mean AC then you would need a step-down transformer with a 4:1 ratio.
Convert 12v to 3v DC?
if you have 12v dc then you can use a 4 ohm resistor
What is the use of position adjuster of multimeter?
How can you see a 1 ohm resistor on a 100k scale ?
What resistor can you use to replace a 47 kilo-ohm resitor?
You should use the same size resistor; a 47 kilo-ohm.CommentThe correct spelling is 'kilohm'.
A 120 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source what is the current running through the 40ohm resitor?
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
