The genotype of the guinea pig with black fur is expressed as (B) because it represents the dominant allele for fur color. In genetic notation, uppercase letters indicate dominant traits, while lowercase letters represent recessive traits. Since black fur is a dominant characteristic, the presence of at least one (B) allele will result in the expression of that trait, regardless of the other allele's state. Thus, a guinea pig with the genotype (BB) or (Bb) will both display black fur.
Genotype codes for phenotype. Phenotype is the expressed trait, for example, black fur. The genome that codes for black fur would be BB for example
White fur
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
In codominance, in which an organism is heterozygous for a trait, both phenotypes are expressed equally because both alleles are dominant. An example is a tortoise shell cat. Tortoise shell cats have both black and orange fur because they have both a dominant black allele and a dominant orange allele for coat color. The black fur is expressed by the allele for black fur and the orange fur is expressed by the allele for orange fur.
If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
No. They might have the same phenotype, but would not have the same genotype.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
they seem to have kurohara hamster in British pet shops. they are quite large (just like guinea pigs) and they have black fur under their stomach
Guinea Pigs are born with fur. I am not sure about hamsters.
yes they are the only rodent that is born with fur
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.