this is not an easy question. Assuming these are incandescent lamps with tungsten filaments, we need to know the type and rating of the lamps (bulbs) and the voltage. Incandescent lamps are highly non-linear and vary greatly in resistance depending on temperature--at lower voltage, the temperature is lower and the resistance is less. The problem is finding the stable operating point at the lower voltage.
Probably the easiest way to answer this is build the circuit and measure.
As a general rule, if the two in series bulbs are equal wattage, each one will dissipate 1/3 of its rated wattage (at half voltage). So two 25W bulbs in series will each dissipate about 8W, or 16W total.
A: There is no such a thing as simple circuit if the bulbs are put in series the light will dim if put in parallel both bulbs will light up the same provided the source can sustain the power increase
Since the bulbs are in series, each one will have 40 volts across it instead of the 120 volts it was designed for. The bulbs will glow very dimly or not at all.
All the bulbs should be the same brightness because they are all receiving the same voltage, which would be half the voltage of the original source. To visualize why this is the case, imagine the electrons moving through the circuit. The electrons can take two paths through the circuit but either way they have to pass through two light bulbs. The two bulbs in parallel may, however, appear slightly dimmer because the current is split between them and restricted by the third bulb. Assume that the resistance of all light bulbs are equal. The current through the light bulbs in parallel will be 1/2 that through the one in series as it is split equally between the two of them. The intensity of each light bulb is proportional to the power through each bulb. Power is I2R. So, if the total current is 1 amp the power through the series light bulb is R, where the power through the parallel light bulbs will be 1/4R. Therefore the intensity of the parallel bulbs will be 1/4 the light bulb in series.
The brightness of a light bulb is related to its power. In all electrical circuits, power is equal to Voltage*Current. Since the two bulbs are connected in series, they must have equal current. The voltage across any given element in a series circuit is proportional to its resistance, so whichever bulb has the higher resistance has a higher voltage and thus higher power and is brighter.
you can use an oingion but not a carrot
The power of light bulbs is measured in
A: There is no such a thing as simple circuit if the bulbs are put in series the light will dim if put in parallel both bulbs will light up the same provided the source can sustain the power increase
The battery should be 4.5 v which is three 1.5 v cells in series. The power in watts depends on the size of the bulbs.
The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.
Power dissipated by the entire series circuit = (voltage between its ends)2 / (sum of resistances of each component in the circuit). Power dissipated by one individual component in the series circuit = (current through the series circuit)2 x (resistance of the individual component).
When two light bulbs are connected in series , there is voltage drop which causes the second lamp to dimAnswerWhen two lamps are connected in series, neither lamp will be subject to its rated voltage and, so, each lamp will be dim. Surprisingly, perhaps, the lamp with the higher power will be dimmer than the lamp with the lower power!
Since the bulbs are in series, each one will have 40 volts across it instead of the 120 volts it was designed for. The bulbs will glow very dimly or not at all.
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.
the power source
All the bulbs should be the same brightness because they are all receiving the same voltage, which would be half the voltage of the original source. To visualize why this is the case, imagine the electrons moving through the circuit. The electrons can take two paths through the circuit but either way they have to pass through two light bulbs. The two bulbs in parallel may, however, appear slightly dimmer because the current is split between them and restricted by the third bulb. Assume that the resistance of all light bulbs are equal. The current through the light bulbs in parallel will be 1/2 that through the one in series as it is split equally between the two of them. The intensity of each light bulb is proportional to the power through each bulb. Power is I2R. So, if the total current is 1 amp the power through the series light bulb is R, where the power through the parallel light bulbs will be 1/4R. Therefore the intensity of the parallel bulbs will be 1/4 the light bulb in series.
1.3 decilion light bulbs for a single second.
Most light bulbs waste energy as heat. Even LEDs. Large light bulbs require more power.