NA(OH)2 is actually sodium hydroxide. The sodium (NA) cation carries a +2 charge, and the hydroxide (OH) anion carries a -1 charge. To balance the equation you must have 2 hydroxide ions to make the anionic charge total -2 to match the cationic +2 charge. It is used to make soaps, cleaners, and hydrogen gas in an aqueous solution when exposed to electrical current. It is a highly corrosive base and should be handled with caution.
You just take your table salt which is nacl . 2nacl+h2o-- naoh2+cl2
No because you have an extra H. Sodium hydroxide is NaOH.
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
It's not possible to determine whether an acid or base is either strong or weak. The only way is to see it's concentration. To determine whether the liquid is an acid or base is easy. An acid's chemical formula always has Hydrogen ions. Example HNO3 or HCl. Bases always have OH or Hydroxide. Example NaOH2.
It's may have been plated for use in jewelry, or more likely was used in a high-school chemistry experiment. I forget the details but there's a compound (NaOH2 ?) that reacts with copper to turn it a goldish color. Either way it's not worth anything as a rarity but it makes an interesting conversation piece.
To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any periodic table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 2 grams NaOH.
Al + NaOH Um this is the "equation" of aluminum and Sodium Hydroxide... Na2CO3(aq) + NaOH (aq) --> NO reaction Sodium carbonate + Sodium hydroxide yields no visible reaction