To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any Periodic Table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about 2 grams NaOH.
The molar mass for NaOH is 40.00g.
Sodium (Na) is 22.99g, Oxygen (O) is 16.00g, and Hydrogen (H) is 1.01g.
Therefore if you have 80.00g of NaOH, there are two moles.
80.00g/40.00g = 2.
n=m/M
m(NaOH2)= 400mg=400x10^-3g
M(NaOH2)=22.99+16.00+2x1.008
NaOH is 40 molecular weight, so 4g means there is 0.1 moles present.
Moles = weight (in g) / molecular weight = 40 / 40 = 1 mole.
So 40 g of sodium hydroxide = 1 mole.
4,0g of sodium hydroxide is equivalent to 0,1 moles.
2 g NaOH means 0.05 moles
2.0
5 mols
0.75 moles in 30.0g of NaOH.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
You need 2,4 g NaOH (0,06 moles).
The same number of moles for each.
0.75 moles in 30.0g of NaOH.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
208g NaOH
The number of moles is 0,0038.
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
You need 2,4 g NaOH (0,06 moles).
The same number of moles for each.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH