Beryllium Iodide has 1 atom of Beryllium and 2 atoms of Iodine. BeI2 is the correct formula for this compound.
0.02 moles of beryllium diiodide = 5,256 grams
Be3N2 That is 3 beryllium atoms + 2 Nitrogen atoms
Formula: BeAs2
BeCO3
Be(MnO4)2
Beryllium. And it's an element, not a chemical.
Beryllium iodide (BeI2) is an ionic compound composed of beryllium cations (Be2+) and iodide anions (I-). It is a white crystalline solid with a high melting point.
We know that the alkaline earth metal beryllium (Be) and the halogen chlorine (Cl) form the ionic compound beryllium chloride (BeCl2). The equation might look like this:Be + Cl2 => BeCl2
Beryllium Iodide
Covalent
To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.
0.02 moles of beryllium diiodide = 5,256 grams
BaI2 is the chemical formula for Barium Iodide.
Compound Bal2 is also known as Barium iodide.
The chemical formula for beryllium fluoride is BeF2.
Formula: AuI
the formula for the compound chromic iodide