0.02 moles of beryllium iodide is equal to 5,256 g.
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
There are 2.04 vaginas in a mole so techinically speaking there 5 7 moles in your moms vagina! which mean thats 7 moles will die from lack of food! which they will then weigh .6grams each. So 7 times 2.04 vaginas is 14.28 moles. Then you take 14.28 moles times .6 grams which equals sperm! :P
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.
The molar mass of gold is approximately 197 grams/mol. To convert moles to grams, you multiply the number of moles by the molar mass. Therefore, 2.8 moles of gold would be approximately 2.8 * 197 = 551.6 grams.
0.02 moles of beryllium diiodide = 5,256 grams
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
There are 2.04 vaginas in a mole so techinically speaking there 5 7 moles in your moms vagina! which mean thats 7 moles will die from lack of food! which they will then weigh .6grams each. So 7 times 2.04 vaginas is 14.28 moles. Then you take 14.28 moles times .6 grams which equals sperm! :P
The formula is: number of moles = g Be/9,012.
16 grams of oxygen how many moles is 0,5 moles.
530,3 g potassium iodide are needed.
53 grams ÷ 18.01 grams/mole = 2.94 moles
120 grams of calcium contain 2,994 moles.
1,8 grams of fluorine is equivalent to 0,0947 moles.
0.377 grams of Kr is equal to 0,0045 moles.
124 grams of ethane is equal to 4,124 moles.
320 grams of oxygen is the equivalent of 10 moles.