The gravitational field strength of a planet multiplied by an objects mass gives us the weight of that object, and that the gravitational field strength, g of Earth is equal to the acceleration of free fall at its surface, 9.81ms − 2.
remote sensing
If the Earth were to lose its magnetic field, things would get a lot more interesting. We'd get a lot more ionizing radiation at the surface, which would result in more mutations (and more deaths).
The equator is the center of the earth's surface which is an equal distance from each pole. The poles are points on both sides of the earth which supposedly create the magnetic field around the earth.
Evidence of changes in Earth's magnetic field is found in rocks through the study of their magnetic minerals, which can record the direction and intensity of the magnetic field at the time of their formation. When volcanic or sedimentary rocks cool or are deposited, iron-bearing minerals align with the Earth's magnetic field, preserving a "fossil" record of its orientation. This phenomenon, known as paleomagnetism, allows scientists to detect shifts in the magnetic poles and changes in the field's strength over geological time. Analyzing these magnetic signatures helps reconstruct past continental movements and understand the dynamics of Earth's magnetic field.
The Most Energetic Cosmic Rays Are Dangerous Because They Are Ionising Radiation. Fortunately, On Earth We Have Two Very Effective Line Of Defence: The Earths Magnetic Field And Its Atmosphere! x
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
Mercury's gravitational field strength is approximately 3.7 m/s^2, which is about 38% of Earth's gravitational field strength. This means that objects on the surface of Mercury would weigh less compared to Earth due to the lower gravitational pull.
The gravitational field strength at the Earth's surface is approximately 10 N/kg (or 10 m/s^2) due to the mass of the Earth and the distance from its center. This value is a result of the acceleration experienced by objects in free fall near the Earth's surface.
The gravitational field strength on Venus is about 8.87 m/s^2, which is about 91% of Earth's gravitational field strength. This means that objects on Venus would feel slightly lighter compared to on Earth.
Not very strong in comparison with a typical small "bar magnet" which has a field strength of roughly 100 gauss. Earth's magnetic field strength at the surface is about 0.3 to 0.6 gauss. That's stronger than some planets and weaker than others.
Yes, the Earth's magnetic field is relatively strong, with a strength of about 25-65 microteslas at the surface. This magnetic field is primarily generated by movement in the planet's outer core.
Earth's magnetic field is about 25 to 65 microteslas in strength at the surface. The magnetic field extends from the Earth's interior out into space, creating a protective buffer against solar wind and cosmic radiation.
If a planet has twice the mass of Earth and its radius is increased by a factor of 2, the gravitational field strength at its surface can be calculated using the formula ( g = \frac{GM}{R^2} ). Here, ( G ) is the gravitational constant, ( M ) is the mass, and ( R ) is the radius. By doubling the radius while doubling the mass, the gravitational field strength becomes ( g' = \frac{2G(2M_E)}{(2R_E)^2} = \frac{G M_E}{R_E^2} ), which equals Earth's gravitational field strength. Thus, the conditions for gravitational strength to be the same as on Earth are satisfied.
The gravitational field strength at the surface of Earth is approximately 9.81 m/s^2, which is effectively the same as the acceleration due to gravity or the acceleration of free fall. This value is commonly used to represent the rate at which objects accelerate towards the Earth when dropped.
The strength of the Earth's magnetic field is about 25 to 65 microteslas.
The known magnitude of Earth's magnetic field at the surface is about 25 to 65 microteslas. This field strength can vary slightly depending on the location on Earth and over time due to changes in the planet's core.
The acceleration due to gravity on the surface Venus is 8.9m/s2 That's about 90% of Earth's.