Assuming you're asking about the chemical formula... Sn(CH3COO)4
Tin(IV) acetate has the chemical formula (not symbol) Sn(C2H3O2)4.
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Stannous = tin(II). Stannic = tin(IV). So stannous acetate is Sn(C2H3O2)2.
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Parts of the zinc near its interface with an aqueous solution of tin acetate dissolve into zinc cations in the soution, and the corresponding electrical charge of tin cations is reduced to metallic tin, usually adhering to the surface of the remaining zinc.
There would be no reaction because tin will not replace the chromium in the chromium (III) acetate. Refer to the related link for an activity series for metals.
Lead (IV) acetate is best written: Pb(CH3COO)4 though occasionally it is seen Pb(C2H3O2)4.
No. They are metallic lead, usually alloyed with tin and antimony.
The chemical formula of lead acetate is Pb(CH3COO)4.
Yes, tin will react with sulphuric acid as it is reactive enough. Metals which are higher than hydrogen in the reactivity series will react with sulphuric acid.
Silver Acetate. It can also be called Silver Ethanoate and its formula can also be written as CH3COOAg.
stannic acetate is a ternary compound of ions (Sn+4 + C2H3O2-). So you'd get Sn(C2H3O2)4Just balance out each side according to its charge.Source- College chemisty student, my textbook, and the same problem in my book which follows the same rules.