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Because energy mass conservation will not be satisfied in free space, so that this process needs some material by which this conversion will be proceed.

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When photon disappear in producing an electron and a positron is the energy of photon equivalent to that of the particles produced?

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What are the possible modes of photon disintegration?

Photon disintegration can occur through the photoelectric effect, Compton scattering, and pair production. In the photoelectric effect, a photon is absorbed by an atom, ejecting an electron. Compton scattering involves a photon colliding with an electron, causing the photon to lose energy and change direction. Pair production occurs when a photon interacts with the nucleus of an atom, producing an electron-positron pair.


Describe what happens when a positron and an electron collide?

They destroy each other and create a gamma photon.


The collision of one electron and one positron produces one or two photons?

This supposition is not true. Mutual annihilation, which occurs when a positron combines with an electron, will result in the conversion of all of the mass of both particles into energy. And this will result in the formation of two photons. The production of the photon pair is the result of conservation laws, and the two photons leave the event in opposite directions. Use the related link below to learn more.


What happens when a positron and a electron collide?

When a positron and an electron collide, they annihilate each other and produce gamma rays. This process is known as electron-positron annihilation. The total energy of the particles is converted into electromagnetic energy in the form of gamma rays.


What is the minimum energy to produce ionization?

The minium required energy of a photon that is involved in the creation of an electron-positron pair (which is pair production), is 1.022 MeV.An electron-positron pair has a given probability of being produced when a photon of the stated energy (or a higher energy) passes close the nucleus of an atom. Pair production does not happen "in the presence of a photon" but happens as a direct result of the the actual presence of a photon (having at least the stated energy) in the presence of an atomic nucleus. The presence of an atomic nucleus is necessary to insure conservation of the quantum mechanical characteristics of the event. Said another way, the high energy photon alone cannot spontaneously create the electron-positron pair in pair production. A link can be found below to related questions.


Why you need 1.022 Mev in pair?

Pair production can only occur if the energy of the photon is bigger than the rest mass (E0 = m0*c^2) of electron and positron, because this is the energy needed to create these particle (conservation of energy). Excess energy will be kinetic energy of the electron and positron. Rest mass of electron and positron is 0.511 MeV each, so 1.022 MeV in total.


What are 4 causes of scatter radiation?

Compton scatter: Interaction between an incoming X-ray photon and an outer-shell electron results in the photon changing direction. Photoelectric effect: Absorption of X-ray photon by inner-shell electron leading to emission of a secondary photon. Pair production: High-energy X-ray photon interacts with atomic nucleus, creating an electron-positron pair. Rayleigh scatter: Low-energy X-ray photon interacts with an atom without ionization, resulting in a scattered photon with the same energy.


If an electron and photon both have energy of 5 mega electron volt which will cause pair production?

pair production only occurs with photons. The necessary condition is that the energy of the photon is greater than that of the two particles that are going to be produced. With 5 mega electron volts as an energy your photon would still not have enough juice as the two smallest particles that can be build are electron and its anti patricle the positron. Both have 511 MeV. You are looking at a trickquestion as neither can.


Can a virtual photon create muon antimuon and tau antitau pair instead of electron positron pair?

Yes, although the heavier pairs are less likely to be found, it is not impossible.


What can be emmited from radioactive decay?

Many particles can be emitted from radioactive decay. We have Internal Conversion in which a nucleus transfers the energy to an electron which then releases it. There is also Isometric Transition which is basically the gamma ray (photon). There is the decay in which a nucleon is emitted. In this scenario we can have an alpha decay (in which an alpha particle decays), a proton emission, a neutron emission, double proton emission (two protons are emitted), spontaneous fission (the nucleus brakes down into two smaller nuclei and/or other particles) and we have the cluster decay (where the nucleus emits a smaller nucleus). There is the beta decay too. There is the Beta decay (electron and electron antineutrino are emitted), positron emission (a positron and an electron neutrino are emitted), electron capture (an electron is captured by the nucleus and a neutrino is emitted), bound state beta decay (the nucleus decays to an electron and an antineutrino but here the electron is not emitted since it is captured into a K-shell), double beta decay (two electrons and two antineutrinos are emitted), double electron capture (the nucleus absorbs two electrons and emits two neutrinos), electron capture with positron emission (an electron is absorbed and a positron is emitted along with two neutrinos), and double positron emission (in which the nucleus emits two positrons and two neutrons).


An excited atom can lose energy by?

An excited atom can lose energy by emitting a photon of light, a process known as spontaneous emission. This photon carries away the excess energy, allowing the atom to return to a lower energy state.