0
What else can I help you with?
Why would a 1986 Toyota corolla 4ac engine tacho bounc up and down?
Becuase you're revving the engine. Becuase you're revving the engine.
Why would a 1986 AE82 Toyota Torolla 4ac engine cut out once the engine starts to warm up if it appears lectrical and you have changed distributer cap ignition coil and ignition module?
Car had a faulty immobilizer that caused the problem.
What are the timing and dwell specs on a 1983 Toyota Corolla with a 4AC engine and a vacuum advance type distributor?
timing: 5 degrees btdc. electronic ignition sets dwell automatically. timing: 5 degrees btdc. electronic ignition sets dwell automatically.
what is the correct quadratic formula?
The roots of the equation [ Ax2 + Bx + C = 0 ] arex = 1/2A [ -B ± sqrt(B2 - 4AC) ]
How do you tell if a discriminant is positive negative or zero?
With the standard notation, If b2 < 4ac then the discriminant is negative If b2 = 4ac then the discriminant is zero If b2 > 4ac then the discriminant is positive
What determine how many solutions a quadratic equation will have and whether they are real or imaginary?
The quadratic equation is: Ax2+ Bx + C = 0-- The equation always has two solutions. They arex = 1/2A [ - B + sqrt(B2 - 4AC) ]x = 1/2A [ - B - sqrt(B2 - 4AC) ] .-- The solutions are real if ( B2 > or = 4AC ).-- The solutions are equal if ( B2 = 4AC ).-- The solutions are complex conjugates if ( B2 < 4AC ).-- The solutions are pure imaginary if ( B = 0 ) & (4AC>0 i.e. -4AC
How do you find the discriminant of a polynomial?
The discriminant of the quadratic equation ax2+bx+c = 0 is the value of b2-4ac When b2-4ac = 0 then there are 2 equal roots. When b2-4ac > 0 then there are 2 different roots. When b2-4ac < 0 then there are no roots at all.
What is the quadratic formula of algebra?
(−b±√b2−4ac)÷2a the square root of b2−4ac entirely.
The Quadratic Formula may be used to solve any quadratic equation?
Yes. But note that if b2 - 4ac is negative, there are no real solutions to the quadratic equation to be found. When complex numbers are used, this is not a problem as sqrt(-1) = i and so if b2 - 4ac is negative, "sqrt(b2 - 4ac)" becomes "i sqrt(4ac - b2)", meaning the solutions are: x = -b/2a + i/2a sqrt(4ac-b2) x = -b/2a - i/2a sqrt(4ac-b2)
What is a x squared plus b x plus c equals 0?
x = (-b (+/-) root( b2 - 4ac)) / 2a Sorry about the messy answer, there are no square root symbols or plus-minus symbols. Here is the proof - ax2 + bx + c = 0 --------> multiply by 4a 4a2x2 + 4abx + 4ac = 0 4a2x2 + 4abx = -4ac ----------> add b2 to both sides 4a2x2 + 4abx + b2 = b2 - 4ac -----------> factorise LHS (2ax + b)2 = b2 - 4ac 2ax + b = (+/-) root( b2 - 4ac) 2ax = -b (+/-) root( b2 - 4ac) x = (-b (+/-) root( b2 - 4ac)) / 2a Maths works people.
How do you get from ax2 bx c to the quadratic formula?
ax2+bx+c=0 Multiply the whole equation by 4a: 4a2x2+4abx+4ac=0 Move the 4ac to the other side: 4a2b2+4abx=-4ac Add b2 to both sides: 4a2b2+4abx+b2=b2-4ac The left side of the equation is like (a+b)2=a2+2ab+b2, with a being 2ab and b being b: (2ax+b)2=b2-4ac Do a square root on both sides of the equation: 2ax+b=√(b2-4ac) Move the b to the other side of the equation: 2ax=-b±√(b2-4ac) Leave only x on the left side of the equation by dividing the right side by 2a: x=(-b±√(b2-4ac))/2a The previous explanation: aX2+bx+c is the same as x=-b (plus or minus the square root) of b2 - 4ac divided by two times a. x=(-b±√(b^2-4ac))/2a x can equal (-b+√(b^2-4ac))/2a ∆ (not delta) (-b-√(b^2-4ac))/2a
What is the formula of the discriminant?
b2-4ac.
