both!
Assuming that each object is held with its center of gravity at the same height, and that each is dropped cleanly, with no rotation induced, the one whose lowest part is closest to the ground when dropped will hit first.
Assuming the object is dropped from rest and neglecting air resistance, it would take approximately 7.0 seconds for the object to hit the ground from a height of 500 feet. This is based on the formula t = sqrt(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity (approximately 32.2 ft/s^2).
They would hit the ground at the same time since both objects fall at the same rate in a vacuum regardless of their mass or size, due to the absence of air resistance on the moon. This is known as the principle of equivalence.
The velocity of the object when it hits the ground can be found using the equation v = sqrt(2 * g * h), where v is the velocity, g is the acceleration due to gravity (9.8 m/s^2), and h is the height (120.0 m). Plugging in the values, we get v = sqrt(2 * 9.8 * 120) = 48.99 m/s. So, the velocity upon hitting the ground is 48.99 m/s.
On the asteroid Ceres, both the hammer and feather would hit the ground at the same time due to the very low gravitational pull compared to Earth. This phenomenon is in line with Galileo's principle that objects of different mass will fall at the same rate in a vacuum.
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
as done in Galileo's experiment when he dropped a large rock and a feather from a tall tower both hit the ground at the same moment when dropped from the same height.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
Both the feather and the hammer will hit the ground at the same time when dropped from the same height in a vacuum. This is due to the principle of gravity, which accelerates all objects at the same rate regardless of their mass.
The higher the ball is dropped from, the higher it will bounce back. This is due to potential energy converting to kinetic energy upon impact with the ground, propelling the ball higher when dropped from greater heights. Ultimately, the bounce height depends on factors like gravity, air resistance, and the material of the ball.
Yes
381 metres
31 m/s
Assuming both were dropped from the same height above ground, in a vacuum both would hit the ground at the same time. In a significant atmosphere (e.g. average ground-level on Earch) the bowling ball would hit the ground first.
Assuming that each object is held with its center of gravity at the same height, and that each is dropped cleanly, with no rotation induced, the one whose lowest part is closest to the ground when dropped will hit first.
19.6 meters / 64.4 ft