It first depends on the type of orbit the satellite is in. If it is in a geostationary orbit, you can determine the speed by using the speed of the Earth's rotation at the equator (465m/sec), because a geostationary satellite orbits above the equator at 22,300 miles above. If it uses a geosynchronous orbit, that is, anywhere else but above the Equator, your distance above the Earth's surface is the same but your speed will differ as the inclination of the satellite is below 90 degrees. If the orbit is a LEO or MEO, your speed will obviously be faster, but the altitude of the satellite has a broader range, so knowing the altitude is essential to your calculation. If the orbit is elliptical, that is an entirely different set of equations, as satellites in elliptical orbits are 300 miles away from the Earth at their fastest to catapult them into their next pass and skyrocket up to 23,000 miles.
Here we will use the following formula velocity of the satellite v = 2πr/T here r is the radius of the circular path travelled by the satellite = 42250 km and T is the time period = 24 hrs. here, the distance travelled by the satellite in 24 hrs would be the circumference of the circular path of radius 42050 . so, v = (2 X 3.14 X 42050) / 24 = 264074 / 24 :)
for the circular motion of a satellite a centripetal force is requid. these force is supplied by the gravitional force between the earth and satellite this is trueall objects in the satellite is zero ie, the object in a satellite feel weightlessness
An artificial satellite orbits the Earth in a stable orbit due to the balance between gravitational force and its inertia. The gravitational pull of the Earth continuously pulls the satellite towards it, while the satellite's forward velocity keeps it moving in a curved path. This combination results in a circular or elliptical orbit, where the satellite's speed remains constant in the absence of atmospheric drag or other forces. Thus, it maintains a consistent distance from the Earth and a stable orbit.
In a circular orbit, a satellite is in free fall and moves with a constant speed, which means that the gravitational force acting on it provides the necessary centripetal force for its circular motion. Since the gravitational force is always perpendicular to the satellite's displacement, the work done on the satellite by gravity is zero. Therefore, no net work is done on a satellite in a stable circular orbit around the Earth.
A satellite can move around the Earth in a circular orbit at a constant height due to the balance between gravitational force and its centripetal force. The gravitational pull of the Earth provides the necessary force to keep the satellite in orbit, while the satellite's velocity ensures it moves forward, creating a continuous circular path. This balance allows the satellite to maintain a stable altitude without falling to Earth or drifting away into space.
Here we will use the following formula velocity of the satellite v = 2πr/T here r is the radius of the circular path travelled by the satellite = 42250 km and T is the time period = 24 hrs. here, the distance travelled by the satellite in 24 hrs would be the circumference of the circular path of radius 42050 . so, v = (2 X 3.14 X 42050) / 24 = 264074 / 24 :)
An artificial satellite travels in a circular orbit around the Earth due to the balance between gravitational force and its inertia. The gravitational pull from the Earth acts as the centripetal force, keeping the satellite in orbit. If the satellite moves at a constant speed, it maintains a stable trajectory, ensuring that the gravitational force is equal to the required centripetal force. This results in a perfect circular orbit, with no change in speed or altitude as long as external forces, such as atmospheric drag, are negligible.
for the circular motion of a satellite a centripetal force is requid. these force is supplied by the gravitional force between the earth and satellite this is trueall objects in the satellite is zero ie, the object in a satellite feel weightlessness
An artificial satellite orbits the Earth in a stable orbit due to the balance between gravitational force and its inertia. The gravitational pull of the Earth continuously pulls the satellite towards it, while the satellite's forward velocity keeps it moving in a curved path. This combination results in a circular or elliptical orbit, where the satellite's speed remains constant in the absence of atmospheric drag or other forces. Thus, it maintains a consistent distance from the Earth and a stable orbit.
In a circular orbit, a satellite is in free fall and moves with a constant speed, which means that the gravitational force acting on it provides the necessary centripetal force for its circular motion. Since the gravitational force is always perpendicular to the satellite's displacement, the work done on the satellite by gravity is zero. Therefore, no net work is done on a satellite in a stable circular orbit around the Earth.
The centripetal force acting on a satellite in uniform circular motion around Earth is directed towards the center of Earth. This force is necessary to keep the satellite moving in a circular path instead of following a straight line.
Yes.
The work done on a satellite in a circular orbit around Earth is zero because the gravitational force acting on the satellite is perpendicular to the direction of motion, so no work is done to maintain the orbit.
low-orbit (satellite)
no
The gravitational force acting on the satellite is provided by the gravitational force between the satellite and the Earth, and is directed towards the center of the Earth. The gravitational force is responsible for causing the satellite to move in a circular path around the Earth. The centripetal force required to keep the satellite in its circular orbit is provided by the gravitational force between the satellite and the Earth.
The direction of motion of a satellite in a circular orbit is perpendicular to the curved surface of the Earth. This means that the satellite moves parallel to the surface at a constant distance rather than following the curve of the Earth.