In theory, yes. I suggest you research "newton's cannon".
A satellite like the space shuttle is in a state of freefall, which means that it is continuously accelerating towards Earth due to gravity, but its forward velocity keeps it in orbit, creating an elliptical path around the planet. This motion can be described as a projectile in a non-accelerated or constant velocity state within the orbital path.
Doubling the mass of a satellite would result in no change in its orbital velocity. This is because the orbital velocity of a satellite only depends on the mass of the planet it is orbiting and the radius of its orbit, but not on the satellite's own mass.
A satellite is in geostationary orbit when it orbits the Earth at the same speed and direction as the Earth's rotation. This allows the satellite to appear stationary from the surface of the Earth. Measurements of its position and velocity can confirm that it is in geostationary orbit.
Escape the earth's gravitational pull and continue out into space. However, a rocket does not need to be launched at the escape velocity as it can continue to accelerate as it climbs. A gun projectile would need to be fired with the escape velocity. In a perfect system with only the projectile and the Earth: If the projectile is fired with the exact escape velocity it will travel to infinity away from the Earth. Upon reaching infinitely far away from Earth the projectile would have zero velocity. All of its kinetic energy (movement) would be transferred to potential energy.
Projectile motion and satellite motion both involve an object moving through a gravitational field. However, satellites are in a state of continuous free fall around a celestial body, while projectiles follow a parabolic path with a defined initial velocity and angle. Additionally, satellites have a stable orbit due to their speed and altitude, while projectiles experience a temporary motion before returning to the ground.
No, a projectile velocity is the initial velocity at which a projectile is launched. The highest velocity a projectile can reach depends on factors such as air resistance, gravity, and propulsion force. In some cases, the velocity of a projectile can increase or decrease after it is launched.
The analytical equation for determining the trajectory of a projectile is the projectile motion equation, which is given by: y xtan - (gx2) / (2v2cos2) where: y is the vertical position of the projectile x is the horizontal position of the projectile is the launch angle g is the acceleration due to gravity (approximately 9.81 m/s2) v is the initial velocity of the projectile
it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
To determine the vertical velocity of a projectile, you can use the formula: vertical velocity initial vertical velocity (acceleration due to gravity x time). The initial vertical velocity is the speed at which the projectile is launched upwards or downwards. Acceleration due to gravity is typically -9.8 m/s2 (negative because it acts downwards). Time is the duration for which the projectile has been in motion. By plugging in these values, you can calculate the vertical velocity of the projectile.
To solve a physics projectile problem, you typically follow these steps: Identify the known variables, such as initial velocity, angle of launch, and acceleration due to gravity. Break down the motion into horizontal and vertical components. Use kinematic equations to calculate the time of flight, maximum height, and range of the projectile. Apply trigonometry to find the horizontal and vertical components of the velocity at any given time. Use these components to solve for the desired quantities, such as final velocity or position at a specific time. By following these steps and applying the appropriate equations, you can successfully solve a physics projectile problem.
A projectile has an initial forward velocity.
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.
To find the average velocity of a projectile, use V = D/T (Velocity equals Displacement over Time).
At the highest point of its trajectory, the direction of an oblique projectile will be horizontal. This means that the projectile will momentarily have zero vertical velocity and only horizontal velocity.
If the projectile is thrown with a greater velocity, it would travel further and potentially reach a higher peak height. The increased velocity would also result in a shorter flight time and the projectile hitting the ground with a greater impact force.