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A rock dropped on the moon will increase its speed from 0 its starting speed to 8.15 in about 5 seconds If you were standing on the moon measuring the rock's motion what would you measure?
That works out at an acceleration of 1.63 m/s2(Presumably you meant 8.15 meters per second.)You would measure how far the rock dropped in 5 seconds. Then you could work out the final speed (or acceleration) from the "equations of motion".
Where can you go in a zero gravity chamber?
There is no such thing as a zero gravity chamber. The only way to experience weightlessness is in freefall. There are planes that you can board which will go into dives up to 30 seconds long. During these dives the planes are in freefall. Since you are falling at the same rate as the plane is, you will seem to float around the cabin and will feel weightless. It is the same reason that astronauts in orbit are weightless.
Where did gravity come from. What did Gravity come from. and When did Gravity come into being?
Of those three questions, the only one that makes any sense is the last one. Gravity doesn't come from a place (the "Where" part) or a thing (the "What" part). Gravity is strongly suspected to have come into existence at the time of the Big Bang, along with the other three fundamental forces. If the Theory of Everything people are right, at extremely high energies the forces combine; gravity would probably have been the first to separate out, at about one Planck time after the Big Bang (a "Planck time" is about 5 x 10-44 seconds).
What country was gravity discovered?
Well, back when the first human was around, I don't think there were any countries. However, Gnarl Tukee of the Gnishmash clan I believe discovered it a few seconds before he fell to his death.
What can a person do to simulate on the moon?
Well, you'd need a vacuum chamber however large you need to simulate whatever you are doing. There is no other way, as air will make dust etc. billow instead of falling like gravel. And you would need to simulate low gravity. The only known way to do this is to be inside the so-called "vomit comet" plane, which can simulate low gravity for a few seconds at a time. Attempts to simulate low gravity with wire rigs simply don't work. The astronauts trained on such, but when they got to the Moon, found out that they needed to move differently than they thought, from the training. Really, there is no way to simulate the Moon, while on the Earth. Can you see moon hoaxers building a vacuum chamber seventeen miles long, to simulate the 17 miles the Rover traveled, transmitting camera and all? How do you simulate low gravity on something to large to fit in a Vomit Comet?
How equation of motion are modified for freely falling objects?
For freely falling objects, the equation of motion is modified to account only for the effects of gravity. The equation becomes: y = 0.5gt^2, where y is the height of the object at time "t" in seconds, and "g" is the acceleration due to gravity (approximately 9.8 m/s^2). Friction and other forces are typically ignored in these scenarios.
What is the velocity of freely falling objects 5 seconds after being dropped?
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
How far will a freely falling object fall from rest in 4 seconds?
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
What is the distance an object travels each second for objects falling under constant acceleration?
For objects falling under constant acceleration (such as gravity), the distance an object travels each second is determined by the formula d = 0.5 * a * t^2, where "d" is the distance, "a" is the acceleration, and "t" is the time in seconds. This means that the distance traveled each second will increase quadratically as time passes.
What is the speed of a free falling object ten seconds after its release?
The speed of a free falling object ten seconds after its release will be approximately 98 m/s, assuming the object is in a vacuum and affected by gravity only. This speed is based on the acceleration due to gravity, which is approximately 9.8 m/s^2.
What is the speed of a free falling object after ten seconds from rest?
The speed of a free falling object after ten seconds from rest is approximately 98 m/s. This speed is achieved due to the acceleration of gravity, which is about 9.8 m/s².
What is the speed of the object after falling 2 second?
The object's speed after falling for 2 seconds can be calculated using the formula: speed = acceleration due to gravity (9.81 m/s^2) x time (2 s). Therefore, the speed of the object after falling for 2 seconds would be 19.62 m/s.
What Suppose an object in free fall is dropped from a building it and starting velocity is 0 ms what is the speed of the object after falling 2 seconds?
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s. This value is obtained by multiplying the acceleration due to gravity (9.8 m/s^2) by the time the object has been falling (2 seconds).
How fast is a rock moving after falling for 2.3 seconds?
Acceleration due to gravity is approx 9.8 metres/second2 So after 2.3 seconds, the velocity of the rock is 9.8*2.3 = 22.54 metres/second
What is the final velocity of a stone with an original velocity of 0 falling from a ledge that takes 8 seconds to hit the ground?
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
Suppose a rock in free fall is dropped off a cliff after falling 5 seconds what is it speed?
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
What equation is used to calculate the velocity of a falling objects?
32 feet / second / second. Calculating the velocity of an object falling due to gravity is a complicated process because gravity decreases the further above the Earth you go. There is also a terminal velocity because of the viscosity of the air. Simply though, acceleration due to gravity at the Earth's surface is roughly 9.8m/s2. This means, after 1 second, an object will have achieved a velocity of 9.8m/s. The equation then if the viscosity of air and height above the Earth's surface are ignored is V = 9.8 x S Where V is the velocity and S is the number of seconds it has been falling.
