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How do you calculate the escape velocity of the sun with a given mass of 2 x 10 to the power of 30 kg and its radius is 7 x 10 to the power of 8 meters?
A body in rest on the surface of sphere with given mass and radius has certain potential energy of Ep=-GMm / r. If you want to totally escape the body gravitational influence, you have to calculate how much kinetic energy you have to give the body for it to be able to reach a distance of infinity from the sphere's center, with at least 0 velocity left.
By the law of energy conservation, the initial energy must be equal to final energy:
Ep0 + Ek0 = Ep1 + Ek1
Ep0 = -GMm / r
Ek0 = mve2 / 2
Ep1 = -GMm / inf = 0
Ek1 = m * 0 / 2 = 0,
so:
-GMm / r + mve2 / 2 = 0,
simplyfying:
ve2 / 2 = GM / r,
then:
ve = sqrt(2GM/r)
What else can I help you with?
Why the moon does not escape from the earth?
They orbit around their common centre of gravity, the orbital radius and velocity of both (centripital force) is exactly enough to overcome the force of gravity between them.
What would be the effect on the orbital velocity of satellite if mass of satellite is double?
Doubling the mass of a satellite would result in no change in its orbital velocity. This is because the orbital velocity of a satellite only depends on the mass of the planet it is orbiting and the radius of its orbit, but not on the satellite's own mass.
Radius of the sun in meters?
The radius of the Sun is approximates 695 500 kilometers.
How fast must an object go to leave a planets gravity?
The speed that ab object must travel at to escape a planet's gravity is called escape velocity. This value varies depending on the mass and diameter of the planet. Here are the escape volcities of the eight planets of our solar system. Mercury: 9,400 mph Venus: 23,000 mph Earth: 25,000 mph Mars: 11,000 mph Jupiter: 133,000 mph Saturn: 77,000 mph Uranus: 48,000 mph Neptune: 53,000 mph Note that escape velocity only takes gravity into account and ignores other forces. An object launched from Earth's surface or from any other planet with a substantial atmosphere at escape velocity would be quickly destroyed and slowed down by air resistance.
The ratio of the radius of that of the moon is 10 .The ratio of g on the earth and on the moon is 6 then what is the ratio of the escape velocity from earth's surface to that from the moon's surface?
The escape velocity is given by √2gR Hence it's value Ve on the earth and Vm on the moon is Ve = √2ge.Re Vm = √2gm.Rm Therefore , their ratio = Ve/Vm = √ge.Re/√gm.Rm = √6 x 10 = √60 = 8 nearly
How can one determine how to find escape velocity in a given scenario?
To find escape velocity in a given scenario, you can use the formula: escape velocity square root of (2 gravitational constant mass of the planet / radius of the planet). This formula takes into account the gravitational pull of the planet and the mass and radius of the planet. By plugging in these values, you can calculate the escape velocity needed to leave the planet's gravitational pull.
Is meters the SI unit for radius in linear velocity?
No, the SI unit for radius is meters (m) and the SI unit for linear velocity is meters per second (m/s). Radius and linear velocity are related in rotational motion, where linear velocity is the tangential velocity at a certain radius from an axis of rotation.
The more massive is an object and the smaller is its radius the greater or smaller is the escape velocity from it?
For two bodies with equal radius, the more massive has the greater escape velocity. For two bodies with equal mass, the one with smaller radius has the greater escape velocity. Both conditions listed in the question indicate greaterescape velocity.
How can one calculate angular velocity from linear velocity?
To calculate angular velocity from linear velocity, you can use the formula: Angular velocity Linear velocity / Radius. This formula relates the speed of an object moving in a circular path (angular velocity) to its linear speed and the radius of the circle it is moving in.
How do you convert radians per second to meters per second?
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
What is the centripetal acceleration of an object being swung on a string with a radius of 3 meters at a velocity of 4 meters per second?
Use the formula for centripetal acceleration: velocity squared / radius.
To escape from a planet's an object muct reach a speed called the?
To escape from a planet's gravitational pull, an object must reach a speed called the "escape velocity." This velocity depends on the mass and radius of the planet from which the object is trying to escape.
What is the centripetal acceleration of an object being swung on a string with a radius of 5 meters at a velocity of 4 meters a second?
Use the formula a = v2 / r, with v = velocity (speed, actually) in meters/second, r = radius in meters. The answer will be in meters per square second.
What is the formula to calculate the linear velocity of a wheel when it is rotating at a given angular velocity?
The formula to calculate the linear velocity of a wheel when it is rotating at a given angular velocity is: linear velocity radius of the wheel x angular velocity.
What of a black hole is the radius from a black hole at which the escape velocity is approximately equal to the speed of light?
It is called the Schwarzschild radius
Does the escape velocity on a planet depend upon its density or mass?
No, its depends on the planets gravitational pull
What is the escape velocity from an asteroid with mass 3000 gm and radius of 10 m?
The escape velocity from an asteroid can be calculated using the formula: escape velocity = sqrt(2 * gravitational constant * mass of asteroid / radius of asteroid). Substituting the given values, the escape velocity from the asteroid would be approximately 200 m/s.
