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The force between the two charges increases 16 times.

Coulomb's law equation states:

│F│ = ke │q1q2│/r2

Where (F) is the force acting simultaneously on both point charges (q1) and (q2).

r is the separation distance and ke is a proportionality constant called the Coulomb

constant.

Using above equation, if we double both charges and reduce the distance in half.

│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.

We see that the force turns out 16 times stronger

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11y ago
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12y ago

Exactly like gravity, the electrostatic force is inversely proportional to the square

of the distance between the two objects involved.

So if the distance between two charges is doubled, the force between them is

reduced by a factor of (2)2 = 4.

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7y ago

The force increases to 4 times the original force

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13y ago

it would act as if two electrostaticly charged objects were seperated.

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14y ago

It becomes a quarter its original amount.

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Q: How do you think the electrostatic force between two objects would change if the distance between two objects was doubled?
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