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If a space probe were sent into orbit around sun that brought it as close as 0.5 AU to sun and as far as 5.5 AU what would is orbital period be?
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∙ 15y ago
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∙ 15y ago
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The velocity a rocket must reach to establish an orbit around earth is called?
Orbital velocity, or Close orbital velocity.
The orbital period of Jupiter is very close to 12 years What is the orbital period of an asteroid at the 52 resonance with Jupiter?
it is twelve years. but im only 10 months, and my dads 13 months so im am really sure about this foolish answer.
If a space probe were sent into an orbit around the sun that brought it as close as 0.5 AU to the sun and as far away as 5.5 AU what would its orbital period be?
By Kepler's 3rd Law, The square of the time period is directly proportional to the cube of the length of the semi-major axis of the elliptical orbit. T2 = K R3In our Solar system, if length is expressed in AU and time in years, the constant K = 1. The length of the major axis is 0.5 + 5.5 = 6Hence, length of semimajor axis = R = 6/2 = 3 * T2 = R3 * T2 = 33 * T2 = 27 * T = 271/2 * T = 5.196 years The orbital period would be 5.196 years Kepler's Law calculations are found at the link.
Earth's period of revolution is 8766.15 hours How many times does earth rotate during one revolution around the sun?
Earth rotates once every 24 hours. If you divide 8766.15 by 24, you get pretty close to the number of days in a year. __________ Not quite. 24 hours is the average synodic period of earth, not the rotational (sidereal) period. Earth rotates once every 23 hours, 56 minutes and 4.1 seconds roughly. This turns out to be about 23.93 hours. The orbital period of earth is 8766.152784 hours roughly. So the earth rotates (sidereal) about 366.325 times in a year. See discussion if you doubt this result.
What is the position of the Mars in the solar system?
Mars is in an elliptical orbit around the Sun. The orbital motion is a combination of the "sideways" velocity of Mars and the gravitational pull in the direction of the Sun. Another movement is the rotation of Mars on its axis.
Most asteroids are about 3 AU from the Sun What is the best estimate of the orbital period of a typical asteroid?
5.2 Earth yearsExplanation: Kepler's third law, shown below, relates a planet's orbital period to its orbital radius. T is the planet's orbital period and r is its orbital radius. k is a constant that depends upon the mass of the star at the center of the solar system.soT2 = kr3When AU are used in our solar system, k is 1. To solve, cube the orbital radius, so 33 is 27. Then take the square root of the result. The square root of 27 is close to 5.2, so the period of a typical asteroid is close to 5.2 Earth years.
The velocity a rocket must reach to establish an orbit around earth is called?
Orbital velocity, or Close orbital velocity.
The orbital period of Jupiter is very close to 12 years What is the orbital period of an asteroid at the 52 resonance with Jupiter?
it is twelve years. but im only 10 months, and my dads 13 months so im am really sure about this foolish answer.
What evidence makes astronomers believe that Pluto is strongly influenced by Neptune?
pluto's orbital period is 247.7 years, very close to one and one -half times Neptune's .thus pluto makes two orbit's around the sun for every three made by Neptune.This match of orbital period may have created a cumulative gravitational attraction on Pluto that "tugged" it into it's orbit.
Which orbital gives an electron the greatest probability of being found close to nucleus?
The 1s orbital.
How is the axis of mercury?
It is very close to perpendicular to its orbital plane.
If a space probe were sent into an orbit around the sun that brought it as close as 0.5 AU to the sun and as far away as 5.5 AU what would its orbital period be?
By Kepler's 3rd Law, The square of the time period is directly proportional to the cube of the length of the semi-major axis of the elliptical orbit. T2 = K R3In our Solar system, if length is expressed in AU and time in years, the constant K = 1. The length of the major axis is 0.5 + 5.5 = 6Hence, length of semimajor axis = R = 6/2 = 3 * T2 = R3 * T2 = 33 * T2 = 27 * T = 271/2 * T = 5.196 years The orbital period would be 5.196 years Kepler's Law calculations are found at the link.
What is the orbital motion of the moon?
And eliptical path. Very close to a circle, but not quite.
Why does neptune have the slowest orbital velocity?
because it is one of the lightest planet and it is not that close to the sun
How long it takes your planet to complete one rotaion?
365.243 days -- if you're talking about days it takes for the earth to revolve around the sun. For any planet to rotate around its own axis takes one day -- one of that planet's days. The moon, for instance, is tide-locked to the Earth, so one lunar day is very close to the 28-Earth-day orbital period.
Why 1st period has 2 element and 2nd period has 8 element?
The factor that determines the number of elements in a period is the number of electrons that can be fitted into the orbitals (shells, orbits). The first two elements (Hydrogen and Helium) have one and two electrons, respectively. They fit into the first orbital which is closer to the nucleus than other orbitals. Because this orbital is so small, if you tried to put more than 2 electrons in it, the electromagnetic repulsions between electrons would push the extra electrons out of the first orbital. Only two can ever fit and so only elements can be in period 1. The second orbital is further from the nucleus and so bigger. Therefore, the electrons in it are not as close to each other. The repulsive force is not as great and 8 electrons can be accomodated. Therefore, the next 8 elements ( Lithium, Berylium, Boron, Carbon, Nitrogen, Oxygen, Fluorine, Neon) all fit into period 2. This answer is adequate for most year 11 students. For Year 12/13, You need to consider the shape of the orbitals. Period one has only one s-orbital which accepts two electrons of different "spin". Period 2 has an s-orbital and three p-orbitals at right angle to each other. These can accept two electrons each, of opposite "spin", giving a total of 8.
Is the average orbital velocity of the Earth 66000 miles per hour?
Close enough (70,000 mph).
