If the radius of the Earth were twice the actual number, with the mass of the Earth held constant, the apparent force of gravity would be reduced to one-quarter the previous value.
From the Law of Gravity, F=(GmM)/rr where M is the mass of Earth and m the human mass, G=6.67*10^(-11) r is Earth's radius The force F is F=mg also mg=weight where g is the acceleration due to gravity and m the human mass Putting them together, we get that the acceleration due to gravity g, is g=GM/rr From this, we get that if the mass of the Earth was doubled, then the acceleration due to gravity would be doubled. So, F=m2g this means that the human weight would be doubled as well I think the derivation is correct.
Anybody who lives on Earth experiences gravity.
mass and size It is for this reason that while Saturn is *far* more massive (95x more) than the earth the gravity you would experience there is only about 1.1x that on Earth (so if you weighed 100 pounds on earth you would weigh 110 pounds on Saturn). Saturn is the least dense of all the planets so you would be far from the center thus experience less gravity. email me at RosemaryRockwood@gmail.com for more questons
Even though free fall causes objects on the International Space Station to appear to be weightless, there actually is gravity. Gravity gets weaker as you move away from the Earth, although it still exists. The change in gravity can be calculated with the equation: 1/(Radius^2). The Earth is about 4000 miles in radius, so in the equation, 4000 miles would be R=1. At 4000 miles in altitude, the distance to the center of the Earth would be 8000 miles so it would use R=2 (twice the radius of the Earth). At the space station's altitude of 200 miles, the equation would use R=1.05. 1/(1.05^2) equals about .91, so gravity on the space station is about 91% of the gravity on the Earth.
Yes, there is gravity on the Moon, but it is only about 1/6th of the gravity we experience on Earth. This is because the Moon is much smaller and less massive than Earth.
From the Law of Gravity, F=(GmM)/rr where M is the mass of Earth and m the human mass, G=6.67*10^(-11) r is Earth's radius The force F is F=mg also mg=weight where g is the acceleration due to gravity and m the human mass Putting them together, we get that the acceleration due to gravity g, is g=GM/rr From this, we get that if the mass of the Earth was doubled, then the acceleration due to gravity would be doubled. So, F=m2g this means that the human weight would be doubled as well I think the derivation is correct.
The weight of a body when raised above the Earth to a height equal to its radius will be 1/4 of its weight at the surface of the Earth. This is because the force of gravity decreases with distance from the center of the Earth, following an inverse-square law.
No. You experience Earth's gravity constantly.
If acceleration due to gravity doubled, your weight on Earth would also double. This means that the force of gravity pulling you downward would be twice as strong as it is currently, causing you to feel heavier.
The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. As a result, a gravity of one fourth that on the surface of the Earth would be observable at an altitude equal to the radius of the Earth, i.e. 6400 km. Note: This is up, in the air, not down, into the Earth. This distance is in outer space.In the other direction, the force of gravity gets smaller as one goes deeper into the earth. This is because the mass outside your current radius (as you descend) does not contribute. The mass inside your current radius is proportional to the cube of the radius. Gravity is proportional to this mass divided by the square of the radius. Therefore, gravity decreases linearly with the radius. So the acceleration of gravity is equal to one fourth its value at the earth's surface at one fourth of the earth's radius, or a depth of approximately 4800 km.
It doesn't Earth has more gravity.
The question cannot be answered because the question provides no information on the mass of the "new" earth. Also, if it is a more massive earth then it is more likely to have a denser atmosphere.
Gravity (g)= (GM)/R^2, where G = Universal gravitational constant, whose value is 6.67 X 10^(-11) NM^2/kg^2; M = Mass of heavenly body and R = Radius of heavenly body. Now, As the radius of moon is accordingly less than the radius of the earth, the square of radius will be very less and the mass is also lesser than that of earth, so it won't affect so much. Hence, The moon's gravity is one sixth of earth's gravity as Radius of moon is 1738 km, whereas the radius of Earth is 6371 km, and mass of earth is 6 × 10^24 and mass of moon is 7.36 × 10^22 kg.
Anybody who lives on Earth experiences gravity.
The acceleration due to gravity on Mercury is approximately 3.7 m/s², which is about 38% of the acceleration due to gravity on Earth. This is due to Mercury's smaller mass and radius compared to Earth.
No. Gravity is dependent on two factors: the mass of the object in question and the distance from its center of mass. So gravity at Earth's surface is dependent on its mass and radius, and Earth is the dominant gravitational body for some distance, but elsewhere, other objects dominate with their own gravity.
Since the distance from the Earth's center is doubled, the force will be reduced by a factor of 4.