If the radius of the Earth were twice the actual number, with the mass of the Earth held constant, the apparent force of gravity would be reduced to one-quarter the previous value.
From the Law of Gravity, F=(GmM)/rr where M is the mass of Earth and m the human mass, G=6.67*10^(-11) r is Earth's radius The force F is F=mg also mg=weight where g is the acceleration due to gravity and m the human mass Putting them together, we get that the acceleration due to gravity g, is g=GM/rr From this, we get that if the mass of the Earth was doubled, then the acceleration due to gravity would be doubled. So, F=m2g this means that the human weight would be doubled as well I think the derivation is correct.
Anybody who lives on Earth experiences gravity.
because moon has small density and shorter radius than earth. specially density is more important for calculation of Gravity. there are some stars that have small radius but greater Gravity. why? because they have Larger density
yes.the conditions shall be same as now.bcause da water shall also be influenced by gravity and so the man.
Even though free fall causes objects on the International Space Station to appear to be weightless, there actually is gravity. Gravity gets weaker as you move away from the Earth, although it still exists. The change in gravity can be calculated with the equation: 1/(Radius^2). The Earth is about 4000 miles in radius, so in the equation, 4000 miles would be R=1. At 4000 miles in altitude, the distance to the center of the Earth would be 8000 miles so it would use R=2 (twice the radius of the Earth). At the space station's altitude of 200 miles, the equation would use R=1.05. 1/(1.05^2) equals about .91, so gravity on the space station is about 91% of the gravity on the Earth.
From the Law of Gravity, F=(GmM)/rr where M is the mass of Earth and m the human mass, G=6.67*10^(-11) r is Earth's radius The force F is F=mg also mg=weight where g is the acceleration due to gravity and m the human mass Putting them together, we get that the acceleration due to gravity g, is g=GM/rr From this, we get that if the mass of the Earth was doubled, then the acceleration due to gravity would be doubled. So, F=m2g this means that the human weight would be doubled as well I think the derivation is correct.
No. You experience Earth's gravity constantly.
The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. As a result, a gravity of one fourth that on the surface of the Earth would be observable at an altitude equal to the radius of the Earth, i.e. 6400 km. Note: This is up, in the air, not down, into the Earth. This distance is in outer space.In the other direction, the force of gravity gets smaller as one goes deeper into the earth. This is because the mass outside your current radius (as you descend) does not contribute. The mass inside your current radius is proportional to the cube of the radius. Gravity is proportional to this mass divided by the square of the radius. Therefore, gravity decreases linearly with the radius. So the acceleration of gravity is equal to one fourth its value at the earth's surface at one fourth of the earth's radius, or a depth of approximately 4800 km.
It doesn't Earth has more gravity.
Dan's mass is the same as it is on Earth. His weight, however, is doubled.
Anybody who lives on Earth experiences gravity.
Since the distance from the Earth's center will be doubled, the force or weight will be reduced by a factor of 4.
Gravity (g)= (GM)/R^2, where G = Universal gravitational constant, whose value is 6.67 X 10^(-11) NM^2/kg^2; M = Mass of heavenly body and R = Radius of heavenly body. Now, As the radius of moon is accordingly less than the radius of the earth, the square of radius will be very less and the mass is also lesser than that of earth, so it won't affect so much. Hence, The moon's gravity is one sixth of earth's gravity as Radius of moon is 1738 km, whereas the radius of Earth is 6371 km, and mass of earth is 6 × 10^24 and mass of moon is 7.36 × 10^22 kg.
no.
since gravity is inversly proportional to square of radius. Gravity increases with equater to poles. Gravity is high on poles and less on equator
Since the distance from the Earth's center is doubled, the force will be reduced by a factor of 4.
Dan's mass is the same as it is on Earth. His weight, however, is doubled.