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Is the square of the orbital period of a planet proportional to the cube of the average distance of the planet from the Sun?
Wiki User
∙ 15y ago
Yes, according to Kepler's third law of Planetary Motion.
Wiki User
∙ 15y ago
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How does the distance of planet affect its period of revolution?
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
If the Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun. true or false?
Not totally true.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
AUs
How does the distance from the sun impact the orbital period and velocity of a planet?
The greater the distance, the longer is the orbital period and the slower the velocity. "Kepler's Laws of Planetary Motion" contain mathematical details. Further explanation is given by the work of Isaac Newton and his theory of gravitation. For example, one version of Kepler's 3rd law is : The square of the orbital period (in Earth years) equals the cube of the average distance from the Sun (in Astronomical Units). <<>> The second half of the question can be answered from the above formula. For example, a planet at four times the distance of Earth from the Sun would go round the Sun in eight years. The length of that orbit would be (almost exactly) four times as far as Earth's. So, the planet would travel at half the speed of Earth. In this example, and also generally, the orbital speed is inversely proportional to the square root of the average distance from the Sun.
If a planet had an average distance of 10 au what would it's orbital period be?
It would depend on the star it was orbiting. If it were in our solar system, its orbital period would be little more than 30 years. (Saturn is approximately 9.5 AU from the Sun.)
How does the distance of planet affect its period of revolution?
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
If the Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun. true or false?
Not totally true.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
AUs
Is it true that Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun.?
No it is not true. The second variable is the cube of the semi-major axis.
The square of the orbital period of a planet around the sun is proportional to the cube of the planet's orbital radius?
Yes, spot on, good guess . .
At what distance from the Sun would a planets orbital period be 3 million years?
At what distance from the Sun would a planet's orbital period be 3 million years?
How does the distance from the sun impact the orbital period and velocity of a planet?
The greater the distance, the longer is the orbital period and the slower the velocity. "Kepler's Laws of Planetary Motion" contain mathematical details. Further explanation is given by the work of Isaac Newton and his theory of gravitation. For example, one version of Kepler's 3rd law is : The square of the orbital period (in Earth years) equals the cube of the average distance from the Sun (in Astronomical Units). <<>> The second half of the question can be answered from the above formula. For example, a planet at four times the distance of Earth from the Sun would go round the Sun in eight years. The length of that orbit would be (almost exactly) four times as far as Earth's. So, the planet would travel at half the speed of Earth. In this example, and also generally, the orbital speed is inversely proportional to the square root of the average distance from the Sun.
If a planet has an average distance from the Sun of 9.1 AU, what is its orbital period SHOW YOUR WORK?
To calculate the orbital period of a planet with an average distance from the Sun of 9.1 Astronomical Units (AU), we use Kepler's Third Law of Planetary Motion: P^2 = a^3. Given: a = 9.1 AU Substitute the value of 'a' into Kepler's Third Law to find the orbital period, P: P^2 = (9.1)^3 P^2 = 753.571 AU^3 To find the orbital period P, take the square root of both sides of the equation: P = √753.571 P ≈ 27.45 years Conclusion: A planet with an average distance of 9.1 AU from the Sun has an estimated orbital period of approximately 27.45 Earth years.
What effect has distance of a planet to the sun to its orbital period?
you are chicken
What would be the average distance of a planet from the Sun with a orbital period of 730 days?
Use Kepler's Third Law, and compare with Earth's orbit.
I used Newton's version of Kepler's third law to calculate Saturn's mass from orbital characteristics of its moon Titan?
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
If a planet had an average distance of 10 au what would it's orbital period be?
It would depend on the star it was orbiting. If it were in our solar system, its orbital period would be little more than 30 years. (Saturn is approximately 9.5 AU from the Sun.)
