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Is the square of the orbital period of a planet proportional to the cube of the average distance of the planet from the Sun?
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
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The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
How does the distance of planet affect its period of revolution?
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
If the Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun. true or false?
Not totally true.
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
Does the orbit time of planets increase or decrease as the distance from the sun increases?
The orbit time of planets increases as the distance from the sun increases. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is proportional to the cube of its average distance from the sun.
What effect has distance of a planet to the sun to its orbital period?
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
At what distance from the Sun would a planets orbital period be 3 million years?
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
How does the distance of planet affect its period of revolution?
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
If the Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun. true or false?
Not totally true.
A calculation of how long it takes a planet to orbit the Sun would be most closely related to which Kepler's Law?
Kepler's 3rd law of planetary motion. It states that the square of a planets orbital period is proportional to the cube of a planets distance from a star.In mathematical notationTO2 = k*R03WhereTO = It's orbital periodRO = It's distance from the stark = A constant.
If a planet had an average distance from the sun of 33 AU what would its orbital period be?
To determine the orbital period of a planet at an average distance of 33 AU from the Sun, we can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) in years is proportional to the cube of the semi-major axis (a) in astronomical units: ( P^2 = a^3 ). For a planet at 33 AU, we calculate ( P^2 = 33^3 ), which gives ( P^2 = 35,937 ). Taking the square root, ( P ) is approximately 189.7 years. Thus, the orbital period of the planet would be about 190 years.
What trend can you see between the time for one complete orbit and the distance from the sun?
There is a direct relationship between the time for one complete orbit (orbital period) and the distance from the sun (orbital radius). This relationship is described by Kepler's third law of planetary motion, which states that the square of the orbital period of a planet is proportional to the cube of its average distance from the sun. In simple terms, planets farther from the sun take longer to complete their orbits.
If Mercury has an average distance to the sun of 0.39 AU in to complete sentences explain how to calculate the orbital period?
To calculate the orbital period of Mercury, you can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) of a planet is directly proportional to the cube of the semi-major axis (a) of its orbit. The formula is ( P^2 = a^3 ), where P is the period in Earth years and a is the average distance from the sun in astronomical units (AU). For Mercury, you would substitute ( a = 0.39 ) AU into the equation, yielding ( P^2 = (0.39)^3 ), and then take the square root to find the orbital period. This results in an approximate orbital period of 0.24 Earth years, or about 88 Earth days.
Is it true that Kepler and third law of planetary motion states that the square of a planet's orbital period is proportional to the cube of the average distance between the planet and the sun.?
No it is not true. The second variable is the cube of the semi-major axis.
Who stated that the square of the period of revolution of a planet is proportional to the cube of its mean distance from the sun?
Johannes Kepler stated the relationship in his third law of planetary motion. This law, formulated in the early 17th century, describes the relationship between a planet's orbital period and its average distance from the sun.
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
