It would depend on the star it was orbiting. If it were in our solar system, its orbital period would be little more than 30 years. (Saturn is approximately 9.5 AU from the Sun.)
AUs
Yes, according to Kepler's third law of Planetary Motion.
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
Not totally true.
The planet must be farther from the star than Earth is from the Sun. According to Kepler's third law, a longer orbital period means that the planet must be farther from its star. In fact you could work out its average distance from the star, using Kepler's law.
AUs
you are chicken
Yes, according to Kepler's third law of Planetary Motion.
At what distance from the Sun would a planet's orbital period be 3 million years?
Temperature and orbital period.
Use Kepler's Third Law, and compare with Earth's orbit.
To calculate the orbital period of a planet with an average distance from the Sun of 9.1 Astronomical Units (AU), we use Kepler's Third Law of Planetary Motion: P^2 = a^3. Given: a = 9.1 AU Substitute the value of 'a' into Kepler's Third Law to find the orbital period, P: P^2 = (9.1)^3 P^2 = 753.571 AU^3 To find the orbital period P, take the square root of both sides of the equation: P = √753.571 P ≈ 27.45 years Conclusion: A planet with an average distance of 9.1 AU from the Sun has an estimated orbital period of approximately 27.45 Earth years.
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
Temperature and orbital period.
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
Not totally true.
F is directly porportional to P