It would depend on the star it was orbiting. If it were in our solar system, its orbital period would be little more than 30 years. (Saturn is approximately 9.5 AU from the Sun.)
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
Not totally true.
The average distance from the sun to a planet is its semi-major axis, which is the longest radius of its elliptical orbit.
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
To calculate the orbital period of a planet, you can use Kepler's third law of planetary motion. The formula is T2 (42 r3) / (G M), where T is the orbital period, r is the average distance from the planet to the sun, G is the gravitational constant, and M is the mass of the sun. Simply plug in the values for r and M to find the orbital period of the planet.
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
To determine the orbital period of a planet at an average distance of 33 AU from the Sun, we can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) in years is proportional to the cube of the semi-major axis (a) in astronomical units: ( P^2 = a^3 ). For a planet at 33 AU, we calculate ( P^2 = 33^3 ), which gives ( P^2 = 35,937 ). Taking the square root, ( P ) is approximately 189.7 years. Thus, the orbital period of the planet would be about 190 years.
Temperature and orbital period.
Use Kepler's Third Law, and compare with Earth's orbit.
Kepler's 3rd law of planetary motion. It states that the square of a planets orbital period is proportional to the cube of a planets distance from a star.In mathematical notationTO2 = k*R03WhereTO = It's orbital periodRO = It's distance from the stark = A constant.
To calculate the orbital period of a planet with an average distance from the Sun of 9.1 Astronomical Units (AU), we use Kepler's Third Law of Planetary Motion: P^2 = a^3. Given: a = 9.1 AU Substitute the value of 'a' into Kepler's Third Law to find the orbital period, P: P^2 = (9.1)^3 P^2 = 753.571 AU^3 To find the orbital period P, take the square root of both sides of the equation: P = √753.571 P ≈ 27.45 years Conclusion: A planet with an average distance of 9.1 AU from the Sun has an estimated orbital period of approximately 27.45 Earth years.
Neither. The time required for an object to complete an orbital trip around the sun depends only on its average distance from the sun, whether it happens to be a planet, an asteroid, a school bus, a comet, a feather, or a cloud of gas.
Temperature and orbital period.