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Is the square of the orbital period of a planet proportional to the cube of the average distance of the planet from the Sun?
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
What effect has distance of a planet to the sun to its orbital period?
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
How it's temparature and period of planet revolution related to its distance from the sun?
The temperature of a planet generally decreases with increasing distance from the Sun due to the inverse square law of radiation, where the intensity of sunlight diminishes with distance. Additionally, a planet's period of revolution, or orbital period, increases with distance from the Sun as described by Kepler's Third Law, which states that the square of a planet's orbital period is proportional to the cube of its average distance from the Sun. Therefore, planets that are farther from the Sun tend to have longer orbital periods and, on average, cooler temperatures.
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
How to calculate the orbital period of a planet?
To calculate the orbital period of a planet, you can use Kepler's third law of planetary motion. The formula is T2 (42 r3) / (G M), where T is the orbital period, r is the average distance from the planet to the sun, G is the gravitational constant, and M is the mass of the sun. Simply plug in the values for r and M to find the orbital period of the planet.
At what distance from the Sun would a planets orbital period be 3 million years?
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
If a planet had an average distance from the sun of 33 AU what would its orbital period be?
To determine the orbital period of a planet at an average distance of 33 AU from the Sun, we can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) in years is proportional to the cube of the semi-major axis (a) in astronomical units: ( P^2 = a^3 ). For a planet at 33 AU, we calculate ( P^2 = 33^3 ), which gives ( P^2 = 35,937 ). Taking the square root, ( P ) is approximately 189.7 years. Thus, the orbital period of the planet would be about 190 years.
If a planet has an average distance from the Sun of 9.1 AU, what is its orbital period SHOW YOUR WORK?
To calculate the orbital period of a planet with an average distance from the Sun of 9.1 Astronomical Units (AU), we use Kepler's Third Law of Planetary Motion: P^2 = a^3. Given: a = 9.1 AU Substitute the value of 'a' into Kepler's Third Law to find the orbital period, P: P^2 = (9.1)^3 P^2 = 753.571 AU^3 To find the orbital period P, take the square root of both sides of the equation: P = √753.571 P ≈ 27.45 years Conclusion: A planet with an average distance of 9.1 AU from the Sun has an estimated orbital period of approximately 27.45 Earth years.
A calculation of how long it takes a planet to orbit the Sun would be most closely related to which Kepler's Law?
Kepler's 3rd law of planetary motion. It states that the square of a planets orbital period is proportional to the cube of a planets distance from a star.In mathematical notationTO2 = k*R03WhereTO = It's orbital periodRO = It's distance from the stark = A constant.
Which two of the planet are closely related to their distance from the sun?
Temperature and orbital period.
Is the planetary year dependent on the planet's size or mass?
Neither. The time required for an object to complete an orbital trip around the sun depends only on its average distance from the sun, whether it happens to be a planet, an asteroid, a school bus, a comet, a feather, or a cloud of gas.
