To calculate the orbital period of a planet, you can use Kepler's third law of planetary motion. The formula is T2 (42 r3) / (G M), where T is the orbital period, r is the average distance from the planet to the sun, G is the gravitational constant, and M is the mass of the sun. Simply plug in the values for r and M to find the orbital period of the planet.
To calculate the orbital period using the semi-major axis, you can use Kepler's third law of planetary motion. The formula is T2 (42 / G(M1 M2)) a3, where T is the orbital period in seconds, G is the gravitational constant, M1 and M2 are the masses of the two objects in the orbit, and a is the semi-major axis of the orbit. Simply plug in the values for G, M1, M2, and a to find the orbital period.
And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.
If you decrease a planet's orbital radius, its surface temperature will increase.
You can calculate this with Kepler's Third Law. "The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit." This is valid for other orbiting objects; in this case you can replace "planet" with "satellite". Just assume, for simplicity, that the satellite orbits Earth in a circular orbit - in this case, the "semi-major axis" is equal to the distance from Earth's center. For your calculations, remember also that if the radius is doubled, the total distance the satellite travels is also doubled.
To determine the period of orbit for a celestial body, one can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit. By measuring the semi-major axis of the orbit and the gravitational force acting on the celestial body, one can calculate the period of its orbit.
The period of a planet's revolution can be used to calculate its orbital radius or distance from the sun using Kepler's third law of planetary motion. It can also be used to determine the planet's orbital speed or velocity if its mass is known. Additionally, the period of revolution helps in predicting future positions of the planet along its orbit.
A planet's orbital period is also known as its year.
Orbital period is the time it takes a planet to go around its star once.
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
Mars has an orbital period of approximately 687 Earth days.
Mercury
Yes, spot on, good guess . .
To determine the orbital period of a planet at an average distance of 33 AU from the Sun, we can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) in years is proportional to the cube of the semi-major axis (a) in astronomical units: ( P^2 = a^3 ). For a planet at 33 AU, we calculate ( P^2 = 33^3 ), which gives ( P^2 = 35,937 ). Taking the square root, ( P ) is approximately 189.7 years. Thus, the orbital period of the planet would be about 190 years.
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
That is that planet's "year", or its orbital period.
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Here is the calculation:P squared = A cubedP squared = 3.36 cubedP squared = 37.9330P = 6. 1589