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To calculate the orbital period using the semi-major axis, you can use Kepler's third law of planetary motion. The formula is T2 (42 / G(M1 M2)) a3, where T is the orbital period in seconds, G is the gravitational constant, M1 and M2 are the masses of the two objects in the orbit, and a is the semi-major axis of the orbit. Simply plug in the values for G, M1, M2, and a to find the orbital period.
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How do you calculate the period of a pendulum?
The period of a pendulum can be calculated using the formula T 2(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
A spacecraft orbits an unknown planet at a distance of 5.2 X 107 m from its center the period of its orbit is 52 hrs?
And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.And what is the question?If you want to figure out the mass of the planet: First, use the formula for centripetal acceleration to get the acceleration. Then, use the gravitation formula to calculate the mass required to produce that acceleration.
How do you calculate the period T of an oscillation?
The period of an oscillation can be calculated using the formula T = 1/f, where T is the period and f is the frequency of the oscillation. The frequency is the number of complete oscillations that occur in one second.
How to calculate the period of a pendulum?
The period of a pendulum can be calculated using the formula T 2(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s2).
What method can be used to determine the mass m of each star in a binary star system?
One method to determine the mass of each star in a binary star system is by studying their orbital motion. By observing the period and separation of the stars' orbits, astronomers can calculate the masses using Kepler's laws of planetary motion and Newton's law of universal gravitation.
1.) Halley’s comet has an observed period of 76.3 years. Use Kepler’s 3rd law to calculate the semimajor axis of the comet’s orbit2.) The dwarf planet Makemake is located a distance 45.8 AU from the sun. What is its orbital period in years?
Semimajor Axis of Halley’s Comet Kepler’s 3rd law states: P^2 = a^3 where P is the orbital period in years, and a is the semimajor axis in astronomical units (AU). Given: P = 76.3 \text{ years} We need to solve for a : a^3 = P^2 a^3 = (76.3)^2 a^3 = 5821.69 a = \sqrt[3]{5821.69} a \approx 17.94 \text{ AU} So, the semimajor axis of Halley’s comet’s orbit is approximately 17.94 AU. Orbital Period of Makemake Given: a = 45.8 \text{ AU} Using Kepler’s 3rd law: P^2 = a^3 P^2 = (45.8)^3 P^2 = 96158.552 P = \sqrt{96158.552} P \approx 310 \text{ years} So, the orbital period of Makemake is approximately 310 years.
If a semimajor axis is 2.77au what is period of Ceres years?
Using Kepler's third law, the period (P) of an object in orbit can be calculated using the formula P^2 = a^3, where a is the semimajor axis in astronomical units (au). For Ceres with a semimajor axis of 2.77 au, the period of its orbit around the Sun is approximately 4.61 years.
What must you know in order to find out a planets period of revolution?
Orbital information. You need to know the size of the "semi-major axis". Then you can calculate the orbital period, using Kepler's Third Law.
The period of the planet's revolution can be use to calculate the?
The period of a planet's revolution can be used to calculate its orbital radius or distance from the sun using Kepler's third law of planetary motion. It can also be used to determine the planet's orbital speed or velocity if its mass is known. Additionally, the period of revolution helps in predicting future positions of the planet along its orbit.
Suppose astronomers discover a new planet orbiting your sunthe orbit has a semimajor axis of 2.52 AU what is the planets period of revolution?
The period of revolution can be calculated using Kepler's Third Law: P^2 = a^3, where P is the period in years and a is the semimajor axis in astronomical units (AU). In this case, the period of revolution of the planet would be approximately 4.00 years.
A comet moves in an elliptical orbit around the sun its distance from the sun varies between 1 AU and 7 AU Calculate its orbital period?
Major axis of mentioned comet has length of 8 AU (1 AU at perihelion plus 7 AU at apohelion on the opposite side of Sun). According to Kepler's third law, the square of orbital period is directly proportional to cube of the orbit's major axis. When using astronomical units for distance and sidereal years for time, this simplifies to: T2 = a3, where T - orbital period a - length of major axis We can then calculate that T for a = 8 AU is about 22.62 years.
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
How do you calculate Mars has an orbital period of 1.88 years. In two or more complete sentences?
Mars has an orbital period of approximately 1.88 Earth years, which can be calculated using Kepler's Third Law of planetary motion. This law states that the square of the orbital period (T) of a planet is directly proportional to the cube of the semi-major axis (a) of its orbit: (T^2 \propto a^3). Given that Mars' average distance from the Sun is about 1.52 astronomical units (AU), substituting this value into the equation allows us to derive its orbital period. Thus, Mars takes nearly 687 Earth days to complete one orbit around the Sun.
I used Newton's version of Kepler's third law to calculate Saturn's mass from orbital characteristics of its moon Titan?
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
How do you Determine the mass of a planet?
You can determine the mass of any planet by astronomically determining the planet's orbital radius and period. Then calculate the required centripetal force and equate this force to the force predicted by the law of universal gravitation using the sun's mass
How to calculate the period of a simple harmonic motion?
by using the formula we will calculat time period of simple harmonic motion
When Mercury has an average distance to the sun of 0.39 AU. In two or more complete sentences explain how to calculate the orbital period of Mercury and then calculate it?
According to Kepler's law, the expression P2/a3 is approx equal to 4pi2/GM where P = period,a = average orbital distance = 0.39 AU = 58,343,169,871 metresG = universal gravitational constant = 6.67408*10^-11 m3 kg-1 s-2M = mass of the Sun = 1.989*1030 kilograms.Substituting these values into the expression and solving givesP2 = 59061382597774 seconds2 which implies that P = 7685140 seconds. This equals 88.9 Earth days.
