What is the distance in meters to the Alpha Centauri system?

Answer 1

A light-year is 9.461 x 1012 km., or 9.461 x 1015 meters; you can use this as a conversion factor.

A light-year is 9.461 x 1012 km., or 9.461 x 1015 meters; you can use this as a conversion factor.

A light-year is 9.461 x 1012 km., or 9.461 x 1015 meters; you can use this as a conversion factor.

A light-year is 9.461 x 1012 km., or 9.461 x 1015 meters; you can use this as a conversion factor.

Answer 2

4.3 light-years x 9.5 x 1015 meters / light-year, equals approximately 4.1 x 1016 meters.

4.3 light-years x 9.5 x 1015 meters / light-year, equals approximately 4.1 x 1016 meters.

4.3 light-years x 9.5 x 1015 meters / light-year, equals approximately 4.1 x 1016 meters.

4.3 light-years x 9.5 x 1015 meters / light-year, equals approximately 4.1 x 1016 meters.

Answer 3

The distance to the Alpha Centauri system from Earth is approximately 4.37 light-years, which is equivalent to about 41.3 trillion kilometers or 25.7 trillion miles. This vast distance makes it the nearest star system to our Solar System.

Answer 4

4.3 light-years x 9.5 x 1015 meters / light-year, equals approximately 4.1 x 1016 meters.

Answer 5

A light-year is 9.461 x 1012 km., or 9.461 x 1015 meters; you can use this as a conversion factor.

Answer 6

first you need seconds in one year, then you multiply that by the speed of light, and then multiply that by the amount of lightyears. (24h)x(3600s)x(365days)= 31,536,000 seconds in one years.

Light travels at 299800m/s this is C

(31,536,000s)(299,800,000m/s) ---> seconds cancel out and your left with a unit of length measurement in meters. 9,454,492,800,000,000 meters for one light year.

Multiply this by the amount of light years, 4.37 and you get the exact amount of meters which is 41,316,133,536,000,000m --> 4.1x10^16 m or

41.32 Petameters.

Answer 7

(9.45x10^15 km of one light year)(4.37light years)= 41.3 Petameters or 4.13x10^16 meters